config_nvidia.hpp.in 1.82 KB
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#ifndef CK_CONFIG_NVIDIA_HPP
#define CK_CONFIG_NVIDIA_HPP
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#include "cuda_runtime.h"
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#include "cuda_fp16.h"
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#include "nvToolsExt.h"
#include "helper_cuda.h"
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#define CK_DEVICE_BACKEND_NVIDIA 1
#define CK_USE_AMD_INLINE_ASM 0
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#define CK_EXPERIMENTAL_USE_MORE_COMPILE_STATIC_BLOCKWISE_GENERIC_SLICE_COPY_V1 0
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#define CK_EXPERIMENTAL_USE_MORE_COMPILE_STATIC_THREADWISE_GENERIC_TENSOR_SLICE_COPY_V1R1 0
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#define CK_EXPERIMENTAL_USE_MORE_COMPILE_STATIC_THREADWISE_GENERIC_TENSOR_SLICE_COPY_V1R2 0
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#define CK_EXPERIMENTAL_USE_MORE_COMPILE_STATIC_THREADWISE_GENERIC_TENSOR_SLICE_COPY_V2R1 0
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namespace ck {

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using unsigned_t = uint32_t;
using signed_t   = int;

#if 0 // debug
using index_t = unsigned_t;
#else
using index_t = signed_t;
#endif

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// For some reason, CUDA need this definition, otherwise
//   compiler won't generate optimal load and store instruction, and
//   kernel would produce wrong result, indicating the compiler fail to generate correct
//   instruction,
using float2_t = float2;
using float4_t = float4;
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template <class T>
__device__ void fused_multiply_accumulate(T& d, const T& s0, const T& s1)
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{
    d += s0 * s1;
}

#if 0
__device__ void fused_multiply_accumulate(half& d, const half& s0, const half& s1) { d += s0 * s1; }

__device__ void fused_multiply_accumulate(half& d, const half2& s0, const half2& s1)
{
    d += s0.x * s1.x;
    d += s0.y * s1.y;
}

__device__ void fused_multiply_accumulate(float& d, const half2& s0, const half2& s1)
{
    d += s0.x * s1.x + s0.y * s1.y;
}

__device__ void fused_multiply_accumulate(char& d, const char& s0, const char& s1) { d += s0 * s1; }

// TODO:: this interface is misleading, s0, s1 are actually int8x4
//  need to make a better interface
__device__ void fused_multiply_accumulate(int32_t& d, const int32_t& s0, const int32_t& s1)
{
    d = __dp4a(s0, s1, d);
}
#endif
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} // namespace ck

#endif