ski_thin.py 5.74 KB
Newer Older
Jethong's avatar
Jethong committed
1
2
3
4
5
6
7
8
9
10
11
12
13
# Copyright (c) 2020 PaddlePaddle Authors. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
Jethong's avatar
Jethong committed
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136

import numpy as np
from scipy import ndimage as ndi

G123_LUT = np.array(
    [
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0,
        0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0,
        1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0,
        1, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        1, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0
    ],
    dtype=np.bool)

G123P_LUT = np.array(
    [
        0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1,
        0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,
        0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
    ],
    dtype=np.bool)


def thin(image, max_iter=None):
    """
    Perform morphological thinning of a binary image.
    Parameters
    ----------
    image : binary (M, N) ndarray
        The image to be thinned.
    max_iter : int, number of iterations, optional
        Regardless of the value of this parameter, the thinned image
        is returned immediately if an iteration produces no change.
        If this parameter is specified it thus sets an upper bound on
        the number of iterations performed.
    Returns
    -------
    out : ndarray of bool
        Thinned image.
    See also
    --------
    skeletonize, medial_axis
    Notes
    -----
    This algorithm [1]_ works by making multiple passes over the image,
    removing pixels matching a set of criteria designed to thin
    connected regions while preserving eight-connected components and
    2 x 2 squares [2]_. In each of the two sub-iterations the algorithm
    correlates the intermediate skeleton image with a neighborhood mask,
    then looks up each neighborhood in a lookup table indicating whether
    the central pixel should be deleted in that sub-iteration.
    References
    ----------
    .. [1] Z. Guo and R. W. Hall, "Parallel thinning with
           two-subiteration algorithms," Comm. ACM, vol. 32, no. 3,
           pp. 359-373, 1989. :DOI:`10.1145/62065.62074`
    .. [2] Lam, L., Seong-Whan Lee, and Ching Y. Suen, "Thinning
           Methodologies-A Comprehensive Survey," IEEE Transactions on
           Pattern Analysis and Machine Intelligence, Vol 14, No. 9,
           p. 879, 1992. :DOI:`10.1109/34.161346`
    Examples
    --------
    >>> square = np.zeros((7, 7), dtype=np.uint8)
    >>> square[1:-1, 2:-2] = 1
    >>> square[0, 1] =  1
    >>> square
    array([[0, 1, 0, 0, 0, 0, 0],
           [0, 0, 1, 1, 1, 0, 0],
           [0, 0, 1, 1, 1, 0, 0],
           [0, 0, 1, 1, 1, 0, 0],
           [0, 0, 1, 1, 1, 0, 0],
           [0, 0, 1, 1, 1, 0, 0],
           [0, 0, 0, 0, 0, 0, 0]], dtype=uint8)
    >>> skel = thin(square)
    >>> skel.astype(np.uint8)
    array([[0, 1, 0, 0, 0, 0, 0],
           [0, 0, 1, 0, 0, 0, 0],
           [0, 0, 0, 1, 0, 0, 0],
           [0, 0, 0, 1, 0, 0, 0],
           [0, 0, 0, 1, 0, 0, 0],
           [0, 0, 0, 0, 0, 0, 0],
           [0, 0, 0, 0, 0, 0, 0]], dtype=uint8)
    """
    # convert image to uint8 with values in {0, 1}
    skel = np.asanyarray(image, dtype=bool).astype(np.uint8)

    # neighborhood mask
    mask = np.array([[8, 4, 2], [16, 0, 1], [32, 64, 128]], dtype=np.uint8)

    # iterate until convergence, up to the iteration limit
    max_iter = max_iter or np.inf
    n_iter = 0
    n_pts_old, n_pts_new = np.inf, np.sum(skel)
    while n_pts_old != n_pts_new and n_iter < max_iter:
        n_pts_old = n_pts_new

        # perform the two "subiterations" described in the paper
        for lut in [G123_LUT, G123P_LUT]:
            # correlate image with neighborhood mask
            N = ndi.correlate(skel, mask, mode='constant')
            # take deletion decision from this subiteration's LUT
            D = np.take(lut, N)
            # perform deletion
            skel[D] = 0

        n_pts_new = np.sum(skel)  # count points after thinning
        n_iter += 1

    return skel.astype(np.bool)