Response:
from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:

    for i in range(len(numbers)):
        for j in range(i+1, len(numbers)):
            if abs(numbers[i]-numbers[j]) < threshold:
                return True
    return False


Response:
from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:

    paren_list = paren_string.split()
    paren_list = ["()" if "(" not in paren else "(())" for paren in paren_list]
    return paren_list


Response:
def truncate_number(number: float) -> float:

    integer_part = int(number)
    decimal_part = number - integer_part
    return decimal_part


Response:
from typing import List
def below_zero(operations: List[int]) -> bool:

    balance = 0
    for operation in operations:
        balance += operation
        if balance < 0:
            return True
    return False


Response:
from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:

    # 计算平均值
    mean = sum(numbers) / len(numbers)
    # 计算每个元素与平均值的绝对差异
    differences = [abs(x - mean) for x in numbers]
    # 计算平均绝对偏差
    mad = sum(differences) / len(differences)
    return mad


Response:
from typing import List

def intersperse(numbers, delimeter):

    result = []
    for i in range(len(numbers)):
        result.extend([numbers[i]] + [delimiter] * (len(numbers) - i - 1))
    return result


Response:
from typing import List

def parse_nested_parens(paren_string):

    stack = []
    result = []
    for paren in paren_string.split():
        max_level = 0
        current_level = 0
        for char in paren:
            if char == '(':
                current_level += 1
                max_level = max(max_level, current_level)
            elif char == ')':
                current_level -= 1
        result.append(max_level)
    return result


Response:
from typing import List
def filter_by_substring(strings: List[str], substring: str) -> List[str]:

    result = []
    for s in strings:
        if substring in s:
            result.append(s)
    return result


Response:
from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:

    if not numbers:
        return 0, 1
    total = sum(numbers)
    product = 1
    for number in numbers:
        product *= number
    return total, product


Response:
from typing import List, Tuple

def rolling_max(numbers):

    result = []
    max_value = float('-inf')
    for i in range(len(numbers)):
        if numbers[i] > max_value:
            max_value = numbers[i]
        result.append(max_value)
    return result


Response:
def is_palindrome(string: str) -> bool:

    return string == string[::-1]
def make_palindrome(string: str) -> str:
    """在给定字符串的末尾添加最少的字符，生成回文字符串。算法思路简单：首先找到字符串的最长后缀，如果是回文，将找到的回文后缀前面的字符串反转，追加到给定字符串的末尾。
    >>> make_palindrome('')
    ''
    >>> make_palindrome('cat')
    'catac'
    >>> make_palindrome('cata')
    'catac'
    """
    n = len(string)
    for i in range(n-1, -1, -1):
        if is_palindrome(string[i:]):
            return string[:i] + string[i:][::-1] + string[i:]


Response:
from typing import List
def string_xor(a: str, b: str) -> str:

    res = ""
    for i in range(len(a)):
        if a[i] == b[i]:
            res += "0"
        else:
            res += "1"
    return res


Response:
from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:

    if not strings:
        return None
    longest_string = strings[0]
    for string in strings:
        if len(string) > len(longest_string):
            longest_string = string
    return longest_string


Response:
def greatest_common_divisor(a: int, b: int) -> int:

    while b != 0:
        a, b = b, a % b
    return a


Response:
from typing import List
def all_prefixes(string: str) -> List[str]:

    prefixes = []
    for i in range(len(string)):
        prefix = string[:i+1]
        if prefix not in prefixes:
            prefixes.append(prefix)
    return prefixes


Response:
def string_sequence(n: int) -> str:

    return ' '.join(str(i) for i in range(n+1))


Response:
def count_distinct_characters(string: str) -> int:

    # 将字符串转换为小写，方便统计
    string = string.lower()
    # 使用集合来存储不同的字符
    distinct_characters = set()
    # 遍历字符串，将每个字符添加到集合中
    for char in string:
        distinct_characters.add(char)
    # 返回集合的大小，即不同字符的数量
    return len(distinct_characters)


Response:
from typing import List

def parse_music(music_string):

    note_lengths = []
    note_list = music_string.split('|')
    for note in note_list:
        note_length = 0
        if 'o' in note:
            note_length = 4
        elif 'o|' in note:
            note_length = 2
        elif '|' in note:
            note_length = 1
        note_lengths.append(note_length)
    return note_lengths


Response:
def how_many_times(string: str, substring: str) -> int:

    count = 0
    start = 0
    while True:
        index = string.find(substring, start)
        if index == -1:
            break
        count += 1
        start = index + 1
    return count


Response:
from typing import List

def sort_numbers(numbers):

    word_dict = {
        'zero': 'zero',
        'one': 'one',
        'two': 'two',
        'three': 'three',
        'four': 'four',
        'five': 'five',
        'six': 'six',
        'seven': 'seven',
        'eight': 'eight',
        'nine': 'nine'
    }

    sorted_numbers = sorted(numbers.split())
    sorted_words = [word_dict[num] for num in sorted_numbers]

    return ' '.join(sorted_words)


Response:
from typing import List, Tuple

def find_closest_elements(numbers):

    # 将数字列表按升序排序
    numbers.sort()

    # 初始化最小差值为正无穷大
    min_diff = float('inf')

    # 初始化最接近的两个数字
    closest_nums = (None, None)

    # 遍历数字列表，比较相邻两个数字的差值，更新最小差值和最接近的两个数字
    for i in range(len(numbers) - 1):
        diff = numbers[i+1] - numbers[i]
        if diff < min_diff:
            min_diff = diff
            closest_nums = (numbers[i], numbers[i+1])

    return closest_nums


Response:
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:

    min_num = min(numbers)
    max_num = max(numbers)
    rescaled = [(num - min_num) / (max_num - min_num) for num in numbers]
    return rescaled


Response:
from typing import List, Any
def filter_integers(values: List[Any]) -> List[int]:

    return [x for x in values if isinstance(x, int)]


Response:
def strlen(string: str) -> int:

    return len(string)


Response:
def largest_divisor(n: int) -> int:

    for i in range(n - 1, 0, -1):
        if n % i == 0:
            return i
    return None


Response:
from typing import List
def factorize(n: int) -> List[int]:

    factors = []
    i = 2
    while i * i <= n:
        if n % i:
            i += 1
        else:
            n //= i
            factors.append(i)
    if n > 1:
        factors.append(n)
    return factors


Response:
from typing import List

def remove_duplicates(numbers):

    count_dict = {}
    result = []
    for num in numbers:
        if num not in count_dict:
            count_dict[num] = 1
        else:
            count_dict[num] += 1
    for num in numbers:
        if count_dict[num] == 1:
            result.append(num)
    return result


Response:
def flip_case(string: str) -> str:

    result = ''
    for char in string:
        if char.islower():
            result += char.upper()
        elif char.isupper():
            result += char.lower()
        else:
            result += char
    return result


Response:
from typing import List
def concatenate(strings: List[str]) -> str:

    return ''.join(strings)


Response:
from typing import List
def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:

    result = []
    for s in strings:
        if s.startswith(prefix):
            result.append(s)
    return result


Response:
def get_positive(l: list):

    return [num for num in l if num > 0]


Response:
def is_prime(n):

    if n <= 1:
        return False
    for i in range(2, int(n**0.5) + 1):
        if n % i == 0:
            return False
    return True


Response:
import math

def poly(xs: list, x: float):

    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
    """xs是多项式的系数。find_zero返回poly（x）= 0时的解。find_zero只返回零点，即使有很多。此外，find_zero仅接受具有偶数系数和最大非零系数的列表 x，因为它保证了有解。
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # f(x) = (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    n = len(xs)
    if n % 2 == 0:
        raise ValueError("多项式系数必须为偶数")
    elif n - 1 > 0 and xs[-1] == 0:
        raise ValueError("多项式系数不能全为零")
    else:
        for i in range(n-1):
            if xs[i] == 0 and xs[i+1] == 0:
                return 0
            if xs[i] == 0:
                return 0
            if xs[i] > 0 and xs[i+1] > 0:
                if xs[i] > max(xs[i+1], 0):
                    return 0
            elif xs[i] < 0 and xs[i+1] < 0:
                if xs[i] > max(xs[i+1], 0):
                    return 0
            elif xs[i] > 0 and xs[i+1] < 0:
                if abs(xs[i]) > abs(xs[i+1]):
                    return 0
            elif xs[i] < 0 and xs[i+1] > 0:
                if abs(xs[i]) > abs(xs[i+1]):
                    return 0
            else:
                if abs(xs[i]) > abs(xs[i+1]):
                    return 0
                elif xs[i] > 0 and xs[i+1] > 0:
                    return round(xs[i]-xs[i+1], 2)
                elif xs[i] < 0 and xs[i+1] < 0:
                    return round(-xs[i]-xs[i+1], 2)
                else:
                    return round(math.sqrt(xs[i]**2 + xs[i+1]**2), 2)


Response:
def sort_third(l):

    l_prime = []  # 存放能被3整除的元素
    for i in range(len(l)):
        if i % 3 == 0:
            l_prime.append(l[i])
    l_prime.sort()  # 对能被3整除的元素进行排序
    for i in range(len(l)):
        if i % 3 != 0:
            l[i] = l_prime.pop(0)  # 将能被3整除的元素依次赋值给不能被3整除的位置
    return l


Response:
def unique(l):

    # 移除重复元素
    l = list(set(l))
    # 对列表进行排序
    l.sort()
    return l


Response:
def max_element(l: list):

    return max(l)


Response:
def fizz_buzz(n):

    count = 0  # 初始化计数器
    for i in range(1, n):
        if i % 11 == 0 or i % 13 == 0:  # 判断是否能被11或13整除
            count += str(i).count('7')  # 累积7的出现次数
    return count


Response:
def sort_even(l):

    # 复制列表 l 并得到一个新的列表，使得偶数索引上的元素与原列表相同
    l_prime = l[:]
    for i in range(len(l)):
        if i % 2 == 0:
            l_prime[i] = l[i]
    # 对偶数索引上的元素进行从小到大排序
    l_prime.sort()
    return l_prime


Response:
def encode_cyclic(s: str):

    # 将字符串拆分为组，每个组的长度为3。
    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
    # 在每个组中循环元素，除非该组的元素少于3个。
    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
    return "".join(groups)
def decode_cyclic(s: str):
    """
    接受encode_cyclic函数编码的字符串，返回解码的字符串。
    """
    # 将字符串拆分为组，每个组的长度为3。
    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
    # 在每个组中循环元素，除非该组的元素少于3个。
    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
    # 将每个组重新组合成字符串。
    return "".join(groups)


Response:
def prime_fib(n):

    def is_prime(num):

        if num < 2:
            return False
        for i in range(2, int(num ** 0.5) + 1):
            if num % i == 0:
                return False
        return True
    def fibonacci(n):
        """
        生成斐波那契数列
        参数:
        n (int): 数列长度
        返回值:
        list: 斐波那契数列
        """
        fib = [0, 1]
        for i in range(2, n):
            fib.append(fib[i - 1] + fib[i - 2])
        return fib
    fib_numbers = fibonacci(100)  # 生成一个较大的斐波那契数列
    prime_fib_numbers = []
    for num in fib_numbers:
        if is_prime(num):
            prime_fib_numbers.append(num)
            if len(prime_fib_numbers) == n:
                return prime_fib_numbers[n - 1]
    return None  # 如果找不到第n个斐波那契质数，则返回None


Response:
def triples_sum_to_zero(l: list):

    n = len(l)
    if n < 3:
        return False
    l.sort()
    for i in range(n-2):
        if l[i] > 0:
            return False
        if l[i] + l[i+1] + l[i+2] == 0:
            return True
        l[i] = -l[i]
    return False


Response:
def car_race_collision(n):
    # 初始化计数器
    count = 0
    # 循环n次，表示所有车辆都发生了碰撞
    for i in range(n):
        # 计算当前车辆的速度
        speed = i + 1
        # 循环n次，表示每辆车都以相同的速度行驶
        for j in range(n):
            # 如果发现有一辆车在相遇时具有更长的行驶距离，则认为发生了碰撞
            if j + i >= n:
                count += 1
            else:
                # 计算当前车辆与从右到左行驶的车辆相遇时的时间
                time = (j - i) / speed
                # 如果相遇时间小于0，或者大于等于总时间，则认为发生了碰撞
                if time < 0 or time >= n:
                    count += 1
                else:
                    # 更新速度
                    speed = (speed + j) / 2
    return count


Response:
def incr_list(l: list):

    return [x+1 for x in l]


Response:
def pairs_sum_to_zero(l):

    seen = set()
    for num in l:
        target = -num
        if target in seen:
            return True
        seen.add(num)
    return False


Response:
def change_base(x: int, base: int):

    if x == 0:
        return '0'
    result = ''
    while x > 0:
        remainder = x % base
        if remainder < 10:
            result = str(remainder) + result
        else:
            result = chr(ord('A') + remainder - 10) + result
        x //= base
    return result


Response:
def triangle_area(a, h):

    area = (a * h) / 2
    return area


Response:
def fib4(n):

    if n == 0:
        return 0
    elif n == 1 or n == 2:
        return 2
    else:
        a, b, c, d = 2, 3, 5, 8
        for i in range(4, n+1):
            a, b, c, d = b, c, d, a + b + c + d
        return d


Response:
def median(l: list):

    sorted_list = sorted(l)
    length = len(sorted_list)
    if length % 2 == 0:
        return (sorted_list[length//2-1] + sorted_list[length//2])/2
    else:
        return sorted_list[length//2]


Response:
def is_palindrome(text: str):

    # 去除空格和标点符号，并将字符串全部转换为小写
    text = ''.join(c.lower() for c in text if c.isalnum())
    # 判断反转后的字符串是否与原字符串相等
    return text == text[::-1]


Response:
def modp(n, p):

    result = pow(2, n, p)
    return result


Response:
def encode_shift(s: str):

    return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])
def decode_shift(s: str):
    """
    该函数接受encode_shift函数编码的字符串作为输入，返回解码的字符串。
    """
    return "".join([chr(((ord(ch) - ord("a") - 5) % 26) + ord("a")) for ch in s])


Response:
def remove_vowels(text):

    vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
    result = ''
    for char in text:
        if char not in vowels:
            result += char
    return result


Response:
def below_threshold(l: list, t: int):

    for num in l:
        if num >= t:
            return False
    return True


Response:
def add(x: int, y: int):

    return x + y


Response:
def same_chars(s0, s1):

    # 将字符串转换为集合，去除重复字符
    set0 = set(s0)
    set1 = set(s1)
    # 求两个集合的交集
    common_chars = set0.intersection(set1)
    # 判断交集是否与其中一个集合相等
    return common_chars == set0 or common_chars == set1


Response:
def fib(n: int):

    if n <= 0:
        return None
    elif n == 1 or n == 2:
        return 1
    else:
        a, b = 1, 1
        for _ in range(3, n + 1):
            a, b = b, a + b
        return b


Response:
def correct_bracketing(brackets: str):

    stack = []
    for char in brackets:
        if char == "<":
            stack.append(char)
        elif char == ">":
            if len(stack) == 0 or stack[-1] != "<":
                return False
            stack.pop()
    return len(stack) == 0


Response:
def monotonic(l):

    return l == sorted(l) or l == sorted(l, reverse=True)


Response:
def common(l1: list, l2: list):

    # 先对两个列表进行排序
    l1.sort()
    l2.sort()
    # 取两个列表的交集，并排序
    return sorted(set(l1) & set(l2))


Response:
def largest_prime_factor(n):

    # 从2开始遍历到n的平方根
    # 因为最大质因数不会超过n的平方根
    i = 2
    while i * i <= n:
        if n % i:
            i += 1
        else:
            n //= i
    return n


Response:
def sum_to_n(n: int):

    return sum(range(1, n+1))


Response:
def correct_bracketing(brackets: str):

    stack = []
    for char in brackets:
        if char == "(":
            stack.append(char)
        elif char == ")":
            if len(stack) == 0 or stack[-1] != "(":
                return False
            stack.pop()
    return len(stack) == 0


Response:
def derivative(xs):

    n = len(xs)
    result = [0] * (n - 1)
    for i in range(1, n):
        result[i - 1] = i * xs[i]
    return result


Response:
def fibfib(n):

    if n == 1:
        return 0
    elif n == 2:
        return 1
    elif n == 3:
        return 1
    else:
        a, b, c = 0, 1, 1
        for _ in range(4, n+1):
            a, b, c = b, c, a + b + c
        return c


Response:
def vowels_count(s):

    vowels = ['a', 'e', 'i', 'o', 'u']
    count = 0
    if s[-1].lower() in vowels:
        count += 1
    for i in range(len(s)):
        if s[i].lower() in vowels:
            count += 1
    return count


Response:
def circular_shift(x, shift):

    # 计算整数x的位数
    digits = 0
    temp = x
    while temp > 0:
        digits += 1
        temp //= 10
    # 进行移动操作
    if shift > digits:
        # 反转整数x的各位数字
        result = 0
        for i in range(digits // 2):
            result = result * 10 + x % 10
            x //= 10
        result *= 10
        for i in range(digits % 2):
            result = result * 10 + x % 10
            x //= 10
        return str(result)
    else:
        # 将每一位数字右移shift位
        result = 0
        for i in range(shift):
            result = result * 10 + x % 10
            x //= 10
        return str(result)


Response:
def digitSum(s):
    total = 0
    for c in s:
        if c.isupper():
            total += ord(c)
    return total


Response:
def fruit_distribution(s,n):
    apples = s.split(" ")[0]
    oranges = s.split(" ")[1]
    mangoes = n - int(apples) - int(oranges)
    return int(mangoes)


Response:
def pluck(arr):
    if not arr:
        return []
    min_even = float('inf')
    min_index = -1
    for i, num in enumerate(arr):
        if num % 2 == 0 and num < min_even:
            min_even = num
            min_index = i
    return [min_even, min_index] if min_even != float('inf') else []


Response:
def search(lst):

    # 统计每个整数出现的次数
    count = {}
    for num in lst:
        count[num] = count.get(num, 0) + 1

    # 找到满足条件的最大整数
    max_num = -1
    for num, freq in count.items():
        if freq >= num and num > max_num:
            max_num = num

    return max_num


Response:
def strange_sort_list(lst):

    # 如果列表为空，直接返回空列表
    if not lst:
        return []
    # 找到列表中的最小值
    min_value = min(lst)
    # 创建一个空列表，用于存放结果
    result = []
    # 从最小值开始，依次添加到结果列表中
    while min_value != max(lst):
        result.append(min_value)
        min_value = min(lst)
    return result


Response:
def triangle_area(a, b, c):

    # 判断是否能组成三角形
    if a + b > c and a + c > b and b + c > a:
        # 使用海伦公式计算面积
        s = (a + b + c) / 2
        area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
        return round(area, 2)
    else:
        return -1


Response:
def will_it_fly(q,w):

    if sum(q) <= w and q == q[::-1]:
        return True
    else:
        return False


Response:
def smallest_change(arr):

    n = len(arr)
    changes = 0
    for i in range(n//2):
        left = arr[i]
        right = arr[n-i-1]
        if left != right:
            changes += 1

    return changes


Response:
def total_match(lst1, lst2):

    # 统计两个列表中字符串的总数
    count1 = sum(len(s) for s in lst1)
    count2 = sum(len(s) for s in lst2)
    # 如果两个列表具有相同数量的字符，则返回第一个列表
    if count1 == count2:
        return lst1
    # 如果第一个列表中字符串的数量多于第二个列表，则返回第一个列表
    if count1 > count2:
        return lst1
    # 如果第二个列表中字符串的数量多于第一个列表，则返回第二个列表
    return lst2


Response:
def is_multiply_prime(a):

    def is_prime(num):
        if num < 2:
            return False
        for i in range(2, int(num ** 0.5) + 1):
            if num % i == 0:
                return False
        return True
    primes = []
    for i in range(2, a):
        if is_prime(i):
            primes.append(i)
            if len(primes) >= 3:
                if a % (primes[-1] * primes[-2] * primes[-3]) == 0:
                    return True
                else:
                    primes.pop()
    return False


Response:
def is_simple_power(x, n):

    if x == 1:
        return True
    if n == 1:
        return False
    k = 0
    while n ** k <= x:
        if n ** k == x:
            return True
        k += 1
    return False


Response:
def iscube(a):

    if a < 0:
        a = -a
    root = round(a ** (1/3))
    return root ** 3 == a


Response:
def hex_key(num):

    if num == '0':
        return 0
    elif num == '1':
        return 1
    elif num == '2':
        return 2
    elif num == '3':
        return 3
    elif num == '4':
        return 4
    elif num == '5':
        return 5
    elif num == '6':
        return 6
    elif num == '7':
        return 7
    elif num == '8':
        return 8
    elif num == '9':
        return 9
    elif num == 'A':
        return 10
    elif num == 'B':
        return 11
    elif num == 'C':
        return 12
    elif num == 'D':
        return 13
    elif num == 'E':
        return 14
    elif num == 'F':
        return 15


Response:
def decimal_to_binary(decimal):

    binary = bin(decimal)[2:]  # 将十进制数转换为二进制字符串，去掉前缀'0b'
    binary = '1' + binary.zfill(8)  # 在字符串开头添加一个'1'，然后使用zfill填充到8位
    binary = 'db' + binary  # 在字符串开头添加'db'
    return binary


Response:
def is_happy(s):

    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] != s[i + 1] and s[i] != s[i + 2] and s[i + 1] != s[i + 2]:
            return False
    return True


Response:
def numerical_letter_grade(grades):

    letter_grades = []
    for grade in grades:
        if grade >= 3.7:
            letter_grades.append('A+')
        elif grade >= 3.3:
            letter_grades.append('A')
        elif grade >= 3.0:
            letter_grades.append('A-')
        elif grade >= 2.7:
            letter_grades.append('B+')
        elif grade >= 2.3:
            letter_grades.append('B')
        elif grade >= 2.0:
            letter_grades.append('B-')
        elif grade >= 1.7:
            letter_grades.append('C+')
        elif grade >= 1.3:
            letter_grades.append('C')
        elif grade >= 1.0:
            letter_grades.append('C-')
        else:
            letter_grades.append('D+')
        # 如果输入的成绩小于3.0，则添加'E'
        if grade < 3.0:
            letter_grades.append('E')
    return letter_grades


Response:
def prime_length(string):

    length = len(string)
    if length < 2:
        return False
    for i in range(2, int(length ** 0.5) + 1):
        if length % i == 0:
            return False
    return True


Response:
def starts_one_ends(n):
    count = 0
    for i in range(1, 10):
        if i == 1:
            count += 1
        elif str(i).startswith('1') and str(i).endswith('1'):
            count += 1
    return count


Response:
def solve(N):
    sum = 0
    while N > 0:
        digit = N % 10
        sum += digit
        N = N // 10
    return bin(sum)[2:]


Response:
def add(lst):

    total = 0
    for i in range(len(lst)):
        if i % 2 == 1 and lst[i] % 2 == 0:
            total += lst[i]
    return total


Response:
def anti_shuffle(s):

    words = s.split()
    sorted_words = ["".join(sorted(word)) for word in words]
    return " ".join(sorted_words)


Response:
def get_row(lst, x):

    row_index = []
    for i in range(len(lst)):
        for j in range(len(lst[i])):
            if lst[i][j] == x:
                row_index.append((i, j))
    row_index.sort(key=lambda x: (x[0], -x[1]))
    return row_index


Response:
def sort_array(array):

    if len(array) <= 1:
        return array
    # 判断第一个索引值和最后一个索引值的和是奇数还是偶数
    total_sum = array[0] + array[-1]
    is_odd = total_sum % 2 != 0
    # 根据和的奇偶性进行排序
    if is_odd:
        return sorted(array)
    else:
        return sorted(array, reverse=True)


Response:
def encrypt(s):

    result = ""
    for char in s:
        if char.isalpha():
            if char.islower():
                base = ord('a')
            else:
                base = ord('A')
            rotated_char = chr((ord(char) - base + 2) % 26 + base)
            result += rotated_char
        else:
            result += char
    return result


Response:
def next_smallest(lst):

    if len(lst) < 2:
        return None
    smallest = min(lst)
    second_smallest = float('inf')
    for num in lst:
        if num > smallest and num < second_smallest:
            second_smallest = num
    if second_smallest == float('inf'):
        return None
    else:
        return second_smallest


Response:
def is_bored(S):

    sentences = S.split(".")
    count = 0
    for sentence in sentences:
        words = sentence.strip().split()
        if words[0] == "I":
            count += 1
    return count


Response:
def any_int(x, y, z):

    if not isinstance(x, int) or not isinstance(y, int) or not isinstance(z, int):
        return False
    if x + y == z or x + z == y or y + z == x:
        return True
    return False


Response:
def encode(message):

    vowels = 'aeiouAEIOU'
    encoded_message = ''
    for char in message:
        if char.lower() in vowels:
            if char.lower() == 'a':
                encoded_message += 'C'
            elif char.lower() == 'e':
                encoded_message += 'G'
            elif char.lower() == 'i':
                encoded_message += 'K'
            elif char.lower() == 'o':
                encoded_message += 'Q'
            elif char.lower() == 'u':
                encoded_message += 'S'
            elif char.lower() == 'A':
                encoded_message += 'C'
            elif char.lower() == 'E':
                encoded_message += 'G'
            elif char.lower() == 'I':
                encoded_message += 'K'
            elif char.lower() == 'O':
                encoded_message += 'Q'
            elif char.lower() == 'U':
                encoded_message += 'S'
        else:
            encoded_message += char
    return encoded_message


Response:
def skjkasdkd(lst):
    def is_prime(n):
        if n < 2:
            return False
        for i in range(2, int(n ** 0.5) + 1):
            if n % i == 0:
                return False
        return True
    max_prime = None
    for num in lst:
        if is_prime(num):
            if max_prime is None or num > max_prime:
                max_prime = num
    if max_prime is not None:
        return sum(int(digit) for digit in str(max_prime))
    else:
        return 0


Response:
def check_dict_case(dict):

    if not dict:
        return False
    keys = list(dict.keys())
    if all(isinstance(key, str) and key.islower() for key in keys):
        return True
    elif all(isinstance(key, str) and key.isupper() for key in keys):
        return True
    else:
        return False


Response:
def count_up_to(n):

    def is_prime(num):
        if num < 2:
            return False
        for i in range(2, int(num ** 0.5) + 1):
            if num % i == 0:
                return False
        return True
    primes = []
    for i in range(2, n):
        if is_prime(i):
            primes.append(i)
    return primes


Response:
def multiply(a, b):
    return (a % 10) * (b % 10)


Response:
def count_upper(s):

    vowels = ['A', 'E', 'I', 'O', 'U']
    count = 0
    for i in range(len(s)):
        if i % 2 == 0 and s[i] in vowels:
            count += 1
    return count


Response:
def closest_integer(value):

    # 将字符串分割成数字列表
    num_list = value.split('.')
    # 将数字列表转换为整数列表
    num_list = [int(num) for num in num_list]
    # 找到最接近的整数
    closest_num = num_list[0]
    min_diff = abs(num_list[0] - int(num_list[0]))
    for num in num_list:
        diff = abs(num - int(num))
        if diff < min_diff:
            closest_num = num
            min_diff = diff
        elif diff == min_diff and num > closest_num:
            closest_num = num
    # 根据距离0的方向取整
    for i in range(len(num_list)-1):
        if abs(num_list[i] - int(num_list[i])) == min_diff:
            if num_list[i] < closest_num:
                closest_num = num_list[i]
            elif num_list[i] > closest_num:
                closest_num = num_list[i]
            break
    return closest_num


Response:
def make_a_pile(n):

    result = []
    stones = n
    while n > 0:
        stones += 1
        if n % 2 == 0:
            stones -= n
        n -= 1
        result.append(stones)
    return result


Response:
def words_string(s):

    words = s.split()
    return words


Response:
def choose_num(x, y):
    max_even = -1
    for i in range(x, y+1):
        if i % 2 == 0 and i > max_even:
            max_even = i
    return max_even


Response:
def rounded_avg(n, m):

    if n > m:
        return -1

    total = 0
    count = 0
    for i in range(n, m+1):
        total += i
        count += 1

    average = total / count
    rounded_average = round(average)
    binary_representation = bin(rounded_average)
    return binary_representation


Response:
def unique_digits(x):

    result = []
    for num in x:
        digits = set(str(num))
        if all(int(digit) % 2 != 0 for digit in digits):
            result.append(num)

    return sorted(result)


Response:
def by_length(arr):
    # 对介于1和9之间的整数进行排序
    arr = sorted(filter(lambda x: 1 <= x <= 9, arr))
    # 反转结果数组
    arr.reverse()
    # 用"One"、"Two"、"Three"、"Four"、"Five"、"Six"、"Seven"、"Eight"、"Nine"替换每个数字
    return ["One" if num == 1 else "Two" if num == 2 else "Three" if num == 3 else "Four" if num == 4 else "Five" if num == 5 else "Six" if num == 6 else "Seven" if num == 7 else "Eight" if num == 8 else "Nine" if num == 9 else num for num in arr]


Response:
def f(n):

    result = []
    for i in range(1, n+1):
        if i % 2 == 0:
            result.append(factorial(i))
        else:
            result.append(sum(range(1, i+1)))
    return result
def factorial(num):

    result = 1
    for i in range(1, num+1):
        result *= i
    return result


Response:
def even_odd_palindrome(n):

    even_count = 0
    odd_count = 0
    # 遍历范围内的每个数
    for num in range(1, n+1):
        # 检查是否为偶数且是回文数
        if str(num) == str(num)[::-1] and num % 2 == 0:
            even_count += 1
        # 检查是否为奇数且是回文数
        elif str(num) == str(num)[::-1] and num % 2 != 0:
            odd_count += 1
    return even_count, odd_count


Response:
def count_nums(arr):
    count = 0
    for num in arr:
        if num >= 0:
            count += 1
    return count


Response:
def move_one_ball(arr):
    n = len(arr)
    if n == 0:
        return True
    i = 1
    while i < n:
        if arr[i] < arr[i-1]:
            arr[i], arr[i-1] = arr[i-1], arr[i]
            i -= 1
        else:
            i += 1
    if arr[0] <= arr[1]:
        return False
    else:
        return True


Response:
def exchange(lst1, lst2):

    # 统计lst1中奇数的个数
    odd_count = sum(1 for num in lst1 if num % 2 != 0)
    # 统计lst2中奇数的个数
    odd_count_2 = sum(1 for num in lst2 if num % 2 != 0)
    # 如果lst1和lst2中都有奇数，则无法通过交换得到lst1中的所有元素都是偶数
    if odd_count > 0 and odd_count_2 > 0:
        return "NO"
    # 如果lst1中奇数的个数大于lst2中奇数的个数，则无法通过交换得到lst1中的所有元素都是偶数
    if odd_count > odd_count_2:
        return "NO"
    # 遍历lst2中的元素
    for num2 in lst2:
        # 如果当前元素是奇数，则从lst1中找到一个偶数进行交换
        if num2 % 2 != 0:
            found = False
            for num1 in lst1:
                if num1 % 2 == 0:
                    lst1[lst1.index(num1)] = num2
                    found = True
                    break
            # 如果未找到偶数，则返回"NO"
            if not found:
                return "NO"
    return "YES"


Response:
def histogram(test):

    # 先将字符串转换为小写字母列表
    str_list = test.lower().split()
    # 统计每个小写字母出现的次数
    count_dict = {}
    for s in str_list:
        if s not in count_dict:
            count_dict[s] = 1
        else:
            count_dict[s] += 1
    # 找出出现次数最多的字母
    max_count = max(count_dict.values())
    max_letter = [k for k, v in count_dict.items() if v == max_count]
    # 构造返回结果的字典
    result_dict = {}
    for letter in max_letter:
        result_dict[letter] = max_count
    return result_dict


Response:
def reverse_delete(s,c):

    # 删除c中重复的字符
    for char in c:
        s = s.replace(char, "")

    # 判断是否是回文
    is_palindrome = s == s[::-1]

    return (s, is_palindrome)


Response:
def odd_count(lst):

    result = []
    for i in range(len(lst)):
        count = 0
        for char in lst[i]:
            if char.isdigit() and int(char) % 2 != 0:
                count += 1
        result.append(f"the number of odd elements {count} in the string {i+1} of the input.")
    return result


Response:
def minSubArraySum(nums):

    n = len(nums)
    if n == 0:
        return 0
    # 初始化最小值和当前区间和
    min_sum = float('inf')
    curr_sum = 0
    # 遍历数组，更新最小值和区间和
    for i in range(n):
        curr_sum += nums[i]
        min_sum = min(min_sum, curr_sum)
        if curr_sum > 0:
            curr_sum = 0
    return min_sum


Response:
def max_fill(grid, capacity):
    import math

    n = len(grid)
    m = len(grid[0])

    ans = 0
    for i in range(n):
        for j in range(m):
            if grid[i][j] == 1:
                visited = [[False] * m for _ in range(n)]
                cnt = 0
                q = [(i, j)]
                while q:
                    x, y = q.pop(0)
                    if not visited[x][y]:
                        visited[x][y] = True
                        cnt += 1
                        if grid[x][y] == 0:
                            continue
                        for dx, dy in [(1, 0), (-1, 0), (0, 1), (0, -1)]:
                            nx, ny = x + dx, y + dy
                            if 0 <= nx < n and 0 <= ny < m and not visited[nx][ny] and grid[nx][ny] == 0:
                                q.append((nx, ny))
                if cnt > ans:
                    ans = cnt
                    b = (i, j)

    return ans


Response:
def sort_array(arr):
    def count_ones(num):
        return bin(num).count("1")

    arr.sort(key=lambda x: (count_ones(x), x))
    return arr


Response:
def select_words(s, n):
    if not s:
        return []
    vowels = ['a', 'e', 'i', 'o', 'u']
    words = s.split()
    result = []
    for word in words:
        count = 0
        for letter in word:
            if letter.lower() not in vowels:
                count += 1
        if count == n:
            result.append(word)
    return result


Response:
def get_closest_vowel(word):

    vowels = ['a', 'e', 'i', 'o', 'u']
    for i in range(len(word) - 2):
        if word[i] in vowels and word[i+1] not in vowels and word[i+2] not in vowels:
            return word[i]
    return ""


Response:
def match_parens(lst):

    stack = []
    for s in lst:
        stack.append(s)

    for i in range(len(stack)):
        for j in range(len(stack)):
            if i != j:
                stack[i] = stack[i][::-1] + stack[j]

    for s in stack:
        if not is_balanced(s):
            return 'No'

    return 'Yes'
def is_balanced(s):
    stack = []
    for c in s:
        if c == '(':
            stack.append(c)
        elif c == ')':
            if not stack or stack[-1] != '(':
                return False
            stack.pop()
    return len(stack) == 0


Response:
def maximum(arr, k):

    if k == 0:
        return []
    arr.sort(reverse=True)
    return arr[:k]


Response:
def solution(lst):

    odd_sum = 0
    for i in range(0, len(lst), 2):  # 遍历偶数索引位置
        if lst[i] % 2 != 0:  # 判断元素是否为奇数
            odd_sum += lst[i]
    return odd_sum


Response:
def add_elements(arr, k):

    total = 0
    for num in arr[:k]:
        if num <= 99:
            total += num
    return total


Response:
def get_odd_collatz(n):
    result = []
    while n != 1:
        if n % 2 == 1:  # 如果当前项为奇数
            result.append(n)  # 将当前项添加到结果列表中
        n = n // 2 if n % 2 == 0 else n * 3 + 1  # 根据定义计算下一项
    return sorted(result)  # 对结果列表进行升序排序


Response:
def valid_date(date):

    if not date:
        return False
    year, month, day = date.split('-')
    month = int(month)
    day = int(day)
    if month < 1 or month > 12:
        return False
    if month in [1, 3, 5, 7, 8, 10, 12]:
        max_day = 31
    elif month in [4, 6, 9, 11]:
        max_day = 30
    else:
        max_day = 29
    if day < 1 or day > max_day:
        return False
    return True


Response:
def split_words(txt):

    words = txt.split()
    if ' ' not in txt:
        return words
    else:
        return words
    if ',' not in txt:
        return sum(1 for c in txt if c.isalpha())
    else:
        return sum(1 for c in txt if c.isalpha())
    return sum(1 for c in txt if ord(c) % 2 != 0)


Response:
def is_sorted(lst):

    # 判断列表长度是否小于等于1，如果是直接返回True
    if len(lst) <= 1:
        return True

    # 遍历列表元素，检查是否满足条件
    for i in range(1, len(lst)):
        # 如果当前元素大于前一个元素，或者当前元素与前一个元素相等但出现次数超过2次，返回False
        if lst[i] > lst[i-1] or (lst[i] == lst[i-1] and lst.count(lst[i]) > 2):
            return False

    return True


Response:
def intersection(interval1, interval2):

    start1, end1 = interval1[0], interval1[1]
    start2, end2 = interval2[0], interval2[1]
    # 计算交集的长度
    intersection_length = max(0, min(end1, end2) - max(start1, start2))
    # 判断交集长度是否为质数
    if is_prime(intersection_length):
        return "YES"
    else:
        return "NO"
def is_prime(num):

    if num < 2:
        return False
    for i in range(2, int(num ** 0.5) + 1):
        if num % i == 0:
            return False
    return True


Response:
def prod_signs(arr):
    if not arr:
        return None
    abs_sum = sum(abs(num) for num in arr)
    pos_prod = 1 if arr[0] > 0 else -1
    for num in arr[1:]:
        if num == 0:
            return 0
        pos_prod *= 1 if num > 0 else -1
    return abs_sum * pos_prod


Response:
def minPath(grid, k):
    m, n = len(grid), len(grid[0])
    dp = [[float('inf')] * n for _ in range(m)]
    dp[0][0] = grid[0][0]
    for i in range(m):
        for j in range(n):
            if i + j == k - 1:
                continue
            if i > 0:
                dp[i][j] = min(dp[i][j], dp[i-1][j] + grid[i][j])
            if j > 0:
                dp[i][j] = min(dp[i][j], dp[i][j-1] + grid[i][j])
    path = []
    i, j = m - 1, n - 1
    while i >= 0 and j >= 0:
        path.append(grid[i][j])
        if i == 0:
            j -= 1
        elif j == 0:
            i -= 1
        else:
            if dp[i-1][j] < dp[i][j-1]:
                i -= 1
            else:
                j -= 1
    return path[::-1]
def minimumKpath(grid, k):
    lst_A = sorted(grid)
    lst_B = sorted(grid)
    for i in range(k):
        lst_A[i], lst_B[i] = lst_B[i], lst_A[i]
    return minPath(lst_A, k)


Response:
def tri(n):
    if n == 0 or n == 1:
        return 3
    elif n % 2 == 0:
        return 1 + n // 2
    else:
        return tri(n - 1) + tri(n - 2) + tri(n + 1)
def tribonacci_list(n):
    result = []
    for i in range(n + 1):
        result.append(tri(i))
    return result


Response:
def digits(n):

    if all(int(digit) % 2 == 0 for digit in str(n)):
        return 0
    else:
        odd_product = 1
        for digit in str(n):
            if int(digit) % 2 != 0:
                odd_product *= int(digit)
        return odd_product


Response:
def is_nested(string):

    stack = []
    for char in string:
        if char == '[':
            stack.append(char)
        elif char == ']':
            if stack and stack[-1] == '[':
                stack.pop()
            else:
                return False
    return len(stack) == 0


Response:
def sum_squares(lst):

    modified_lst = [int(num) for num in lst]  # 将列表中的每个元素替换为大于或等于该元素的最小整数
    squared_sum = sum([num**2 for num in modified_lst])  # 计算修改后的列表中每个元素的平方和

    return squared_sum


Response:
def check_if_last_char_is_a_letter(txt):

    words = txt.split()
    if len(txt) > 0 and txt[-1].isalpha() and txt[-1] not in words:
        return True
    return False


Response:
def can_arrange(arr):

    n = len(arr)
    if n <= 1:
        return -1
    max_index = -1
    for i in range(1, n):
        if arr[i] <= arr[i-1]:
            max_index = i
    return max_index


Response:
def largest_smallest_integers(lst):

    negative_nums = [num for num in lst if num < 0]
    positive_nums = [num for num in lst if num > 0]
    if negative_nums:
        a = max(negative_nums)
    else:
        a = None
    if positive_nums:
        b = min(positive_nums)
    else:
        b = None
    return (a, b)


Response:
def compare_one(a, b):

    # 将实数转换为字符串形式
    a_str = str(a)
    b_str = str(b)
    # 获取小数点或逗号的位置
    a_point = None
    b_point = None
    if '.' in a_str:
        a_point = a_str.index('.')
    if ',' in b_str:
        b_point = b_str.index(',')
    # 转换为整数
    a_int = int(a_str)
    b_int = int(b_str)
    # 比较大小
    if a_int > b_int:
        return a_int
    elif a_int == b_int:
        if a_point is not None and b_point is not None:
            if a_point < b_point:
                return a_int
            elif a_point > b_point:
                return b_int
            else:
                return None
        else:
            return a_int
    else:
        if a_point is not None and b_point is not None:
            if a_point < b_point:
                return b_int
            elif a_point > b_point:
                return a_int
            else:
                return None
        else:
            return b_int


Response:
def is_equal_to_sum_even(n):

    # 判断n是否是4的倍数
    if n % 4 != 0:
        return False

    # 计算n/4，判断是否是整数
    if n // 4 != int(n // 4):
        return False

    # 计算n/4的每位数字之和
    digit_sum = sum([int(digit) for digit in str(n // 4)])

    # 判断n是否等于digit_sum的两倍
    if n != 2 * digit_sum:
        return False

    return True


Response:
def special_factorial(n):

    if n == 0:
        return 1
    else:
        result = 1
        for i in range(1, n+1):
            result *= i
        return result


Response:
def fix_spaces(text):

    # 替换连续的空格为'-'
    text = ' '.join(text.split())
    # 替换单个空格为下划线
    text = text.replace(' ', '_')
    # 替换两个连续空格为下划线
    text = text.replace('  ', '_')
    return text


Response:
def file_name_check(file_name):

    import re
    # 数字不能超过3个
    num_count = len(re.findall(r'\d', file_name))
    if num_count > 3:
        return 'No'
    # 文件名长度必须为0
    if len(file_name) == 0:
        return 'No'
    # 文件名必须包含至少一个'.'
    if '.' not in file_name:
        return 'No'
    # 文件名不能以'.'开头或结尾
    if file_name[0] == '.' or file_name[-1] == '.':
        return 'No'
    # 检查'.'之前的子字符串
    username = re.findall(r'([a-zA-Z])', file_name)
    if len(username) == 0:
        return 'No'
    # 检查'.'之后的子字符串
    extension = re.findall(r'\.(txt|exe|dll)', file_name)
    if len(extension) != 1:
        return 'No'
    return 'Yes'


Response:
def sum_squares(lst):

    result = 0
    for i, num in enumerate(lst):
        if i % 3 == 0 or i % 4 == 0:
            if i % 3 == 0:
                result += num ** 2
            else:
                result += num ** 3
        else:
            result += num
    return result


Response:
def words_in_sentence(sentence):

    def is_prime(n):
        if n < 2:
            return False
        for i in range(2, int(n**0.5) + 1):
            if n % i == 0:
                return False
        return True
    words = sentence.split()
    result = []
    for word in words:
        if is_prime(len(word)):
            result.append(word)
    return ' '.join(result)


Response:
def simplify(x, n):

    # 将x和n转化为分数的分子和分母
    x_num, x_den = map(int, x.split('/'))
    n_num, n_den = map(int, n.split('/'))
    # 计算x * n的分子和分母
    result_num = x_num * n_num
    result_den = x_den * n_den
    # 判断x * n是否为整数
    if result_num % result_den == 0:
        return True
    else:
        return False


Response:
def order_by_points(nums):

    def get_digit_sum(num):
        # 计算一个数字的各位数之和
        return sum(int(digit) for digit in str(abs(num)))
    sorted_nums = sorted(nums, key=lambda x: (get_digit_sum(x), nums.index(x)))
    return sorted_nums


Response:
def specialFilter(nums):

    count = 0
    for num in nums:
        if num > 10 and num % 2 != 0 and str(num)[0] in ['1', '3', '5', '7', '9'] and str(num)[-1] in ['1', '3', '5', '7', '9']:
            count += 1
    return count


Response:
def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n+1)]
    count = 0
    for i in range(n-2):
        for j in range(i+1, n-1):
            for k in range(j+1, n):
                if (a[i] + a[j] + a[k]) % 3 == 0:
                    count += 1
    return count


Response:
def bf(planet1, planet2):

    planets = {
        "Mercury": 0.39,
        "Venus": 0.72,
        "Earth": 1.00,
        "Mars": 1.52,
        "Jupiter": 5.20,
        "Saturn": 9.58,
        "Uranus": 19.18,
        "Neptune": 30.07
    }
    if planet1 not in planets or planet2 not in planets:
        return ()
    if planet1 == planet2:
        return planet1
    start_distance = min(planets[planet1], planets[planet2])
    end_distance = max(planets[planet1], planets[planet2])
    result = []
    for planet, distance in planets.items():
        if start_distance <= distance <= end_distance:
            result.append(planet)
    return tuple(sorted(result))


Response:
def sorted_list_sum(lst):

    # 删除长度为奇数的字符串
    lst = [s for s in lst if len(s) % 2 == 0]
    # 按照字符串长度和首字母进行排序
    lst.sort(key=lambda x: (len(x), x[0]))
    return lst


Response:
def x_or_y(n, x, y):
    if n < 2:
        return y
    for i in range(2, int(n ** 0.5) + 1):
        if n % i == 0:
            return y
    return x


Response:
def double_the_difference(lst):

    result = 0
    for num in lst:
        if isinstance(num, int) and num > 0 and num % 2 == 1:
            result += num ** 2
    return result


Response:
def compare(game,guess):
    result = []
    for i in range(len(game)):
        if game[i] == guess[i]:
            result.append(0)
        else:
            result.append(abs(game[i]-guess[i]))
    return result


Response:
def Strongest_Extension(class_name, extensions):

    # 定义一个函数用于计算扩展的强度
    def calculate_strength(extension):
        caps = sum(1 for char in extension if char.isupper())
        sm = sum(1 for char in extension if char.islower())
        return caps - sm
    # 初始化最强扩展为空字符串
    strongest_extension = ''
    # 遍历扩展列表，找到最强的扩展
    for extension in extensions:
        if len(extension) > len(strongest_extension):
            strength = calculate_strength(extension)
            if strength > 0:
                strongest_extension = extension
    # 返回最强扩展的名称
    return class_name + '.' + strongest_extension


Response:
def cycpattern_check(a , b):

    # 如果b为空字符串，则直接返回True
    if not b:
        return True
    # 如果a为空字符串，或者a的长度小于b的长度，则直接返回False
    if not a or len(a) < len(b):
        return False
    # 将b重复一次，如果a是b的子字符串，则返回True
    if a.find(b) != -1:
        return True
    # 将b循环移位，继续判断
    for i in range(len(b)):
        if cycpattern_check(a, b[i:] + b[:i]):
            return True
    # 如果无法通过上述操作得到结果，则返回False
    return False


Response:
def even_odd_count(num):

    even_count = 0
    odd_count = 0
    # 将整数转换为字符串，便于逐位判断
    num_str = str(abs(num))
    # 遍历每个数字字符
    for digit in num_str:
        if int(digit) % 2 == 0:
            even_count += 1
        else:
            odd_count += 1
    return (even_count, odd_count)


Response:
def int_to_mini_roman(number):

    roman_dict = {
        1000: 'M',
        900: 'CM',
        500: 'D',
        400: 'CD',
        100: 'C',
        90: 'XC',
        50: 'L',
        40: 'XL',
        10: 'X',
        9: 'IX',
        5: 'V',
        4: 'IV',
        1: 'I'
    }
    result = ''
    for value, symbol in roman_dict.items():
        while number >= value:
            result += symbol
            number -= value
    return result


Response:
def right_angle_triangle(a, b, c):

    # 判断是否满足勾股定理
    if a**2 + b**2 == c**2 or a**2 + c**2 == b**2 or b**2 + c**2 == a**2:
        return True
    else:
        return False


Response:
def find_max(words):

    max_count = 0
    max_word = ""
    for word in words:
        unique_chars = set(word)
        count = len(unique_chars)
        if count > max_count:
            max_count = count
            max_word = word
        elif count == max_count and word < max_word:
            max_word = word
    return max_word


Response:
def eat(number, need, remaining):
    if remaining < need:
        number = 1000
    elif remaining == need:
        return [number, 0]
    else:
        number += remaining
        return [number, remaining]


Response:
def do_algebra(operator, operand):

    result = None

    if operator == '+':
        result = sum(operand)
    elif operator == '-':
        result = operand[0] - sum(operand[1:])
    elif operator == '*':
        result = 1
        for num in operand:
            result *= num
    elif operator == '/':
        result = operand[0] // operand[1]
    elif operator == '**':
        result = operand[0] ** operand[1]
    return result


Response:
def solve(s):

    # 判断字符串s中的每个元素是否是字母
    for i in range(len(s)):
        if s[i].isalpha():
            # 如果s[i]是字母，则将s[i]从小写转换为大写或从大写转换为小写
            if s[i].islower():
                s = s[:i] + s[i].upper() + s[i+1:]
            else:
                s = s[:i] + s[i].lower() + s[i+1:]
    # 返回处理后的结果字符串
    return s[::-1] if not any(char.isalpha() for char in s) else s


Response:
def string_to_md5(text):
    if not text:
        return None
    else:
        md5_hash = hashlib.md5()
        md5_hash.update(text.encode('utf-8'))
        return md5_hash.hexdigest()


Response:
def generate_integers(a, b):

    if a > b:
        a, b = b, a
    return list(range(a, b+1, 2))