# Copyright (c) 2021 PaddlePaddle Authors. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
"""
This code is based on https://github.com/niecongchong/RS-building-regularization
Ths copyright of niecongchong/RS-building-regularization is as follows:
Apache License [see LICENSE for details]
"""

import numpy as np


# 线生成函数
def line(p1, p2):
    A = (p1[1] - p2[1])
    B = (p2[0] - p1[0])
    C = (p1[0] * p2[1] - p2[0] * p1[1])
    return A, B, -C


# 计算两条直线之间的交点
def intersection(L1, L2):
    D = L1[0] * L2[1] - L1[1] * L2[0]
    Dx = L1[2] * L2[1] - L1[1] * L2[2]
    Dy = L1[0] * L2[2] - L1[2] * L2[0]
    if D != 0:
        x = Dx / D
        y = Dy / D
        return x, y
    else:
        return False


# 计算两个平行线之间的距离
def par_line_dist(L1, L2):
    A1, B1, C1 = L1
    A2, B2, C2 = L2
    new_A1 = 1
    new_B1 = B1 / A1
    new_C1 = C1 / A1
    new_A2 = 1
    new_B2 = B2 / A2
    new_C2 = C2 / A2
    dist = (np.abs(new_C1 - new_C2)) / (np.sqrt(new_A2**2 + new_B2**2))
    return dist


# 计算点在直线的投影位置
def point_in_line(m, n, x1, y1, x2, y2):
    eps = 1e-12
    x = (m * (x2 - x1) * (x2 - x1) + n * (y2 - y1) * (x2 - x1) +
         (x1 * y2 - x2 * y1) * (y2 - y1)) / (
             (x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1))
    y = (m * (x2 - x1) * (y2 - y1) + n * (y2 - y1) * (y2 - y1) +
         (x2 * y1 - x1 * y2) * (x2 - x1)) / (
             (x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1))
    return (x, y)