merged latest and added altworld files

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_abstract_algebra.yaml

@@ -35,7 +35,7 @@
   \ then x^2 + c = x^2 + 1 = 0 + 1 for x = 0, 1 + 1 = 2 for x = 1 and 1 + 1 = 2 for\
   \ x = 2, hence x^2 + 1 does not have any roots. For c = 2 the polynomial x^2 + 2\
   \ has two roots at x = 1 and x = 2. Hence Z_3[x]/(x^2 + c) is a field if and only\
-  \ if c = 1. The answer is (B)."
+  \ if c = 1. The answer is (B).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_abstract_algebra"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_anatomy.yaml

@@ -51,7 +51,7 @@
   \ of the hyoid bone; therefore, the embryological origin of the hyoid bone are the\
   \ second and the third pharyngeal arches—this information is covered in the last\
   \ option (D). Therefore, we conclude that (D) must be the correct answer. The answer\
-  \ is (D)."
+  \ is (D).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_anatomy"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_astronomy.yaml

@@ -49,7 +49,7 @@
   \ red. Options (C) and (D) are not specific enough about why the color of the surface\
   \ would be red, while (A) is correct because it explains that the surface is red\
   \ due to the rusted materials on the surface and the red color comes from the rust.\
-  \ So the correct option is (A). The answer is (A)."
+  \ So the correct option is (A). The answer is (A).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_astronomy"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_business_ethics.yaml

@@ -50,7 +50,7 @@
   \ that best uses the possible options above is “Beyond the business case for engaging\
   \ the CSR there are a number of moral arguments relating to: negative *externalities*,\
   \ the *power* that corporations possess and the *mutual independence* of business\
-  \ and society. The answer is (D)."
+  \ and society. The answer is (D).\n\n"
 "group": "mmlu_flan_cot_fewshot_other"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_business_ethics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_clinical_knowledge.yaml

@@ -29,7 +29,7 @@
   \ (D) oxidative phosphorylation.\nA: Let's think step by step. We refer to Wikipedia\
   \ articles on clinical knowledge for help. The energy for muscular contraction is\
   \ provided by ATP (adenosine triphosphate), which is the powerhouse of the cell.\
-  \ The answer is (A)."
+  \ The answer is (A).\n\n"
 "group": "mmlu_flan_cot_fewshot_other"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_clinical_knowledge"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_biology.yaml

@@ -55,7 +55,7 @@
   \ resemblance of structures that have different origins, which is not the case for\
   \ the human and bird forearms, which rules out (D). Humans and birds do belong to\
   \ the same clade - a group of organisms composed of a common ancestor. The answer\
-  \ is (C)."
+  \ is (C).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_college_biology"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_chemistry.yaml

@@ -32,7 +32,7 @@
   \ hyperfine interaction with the 13C (nuclear spin $I = \nrac{1}{2}$) which will\
   \ split the spectrum into 2 lines. This will be further split into 4 lines by the\
   \ interaction with three equivalent 1H nuclei. The total number of lines is therefore\
-  \ $2 \\cdot 4 = 8$. The answer is (E)."
+  \ $2 \\cdot 4 = 8$. The answer is (E).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_college_chemistry"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_computer_science.yaml

@@ -73,7 +73,7 @@
   Thus we can see that on average a single processor will lock the bus for:\nlock_ns_per_miss\
   \ * misses_per_instruction * instructions_per_ns =\n(1000 nanoseconds / cache miss)\
   \ * (1 cache miss / 50 instructions) * (50 instructions / 27000 nanoseconds) = 1000\
-  \ * (1/50) * (50/27000) = 1000/27000 = 1/27. The answer is (B)."
+  \ * (1/50) * (50/27000) = 1000/27000 = 1/27. The answer is (B).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_college_computer_science"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_mathematics.yaml

@@ -44,7 +44,7 @@
   \ $t \\in \\mathbb{R}, \\ln ((s(t)-2))=-[t / 25]+C$. Let $K:=e^{C}$. Then, for all\
   \ $t \\in \\mathbb{R}$, we have $(s(t))-2=K e^{-t / 25}$, and so $s(t)=2+K e^{-t\
   \ / 25}$. Then $3=s(0)=2+K e^{0}=2+K$, so $K=1$. Then $s(100)=2+K e^{-100 / 25}=2+1\
-  \ \\cdot e^{-4}=2+e^{-4}$. The answer is (D)."
+  \ \\cdot e^{-4}=2+e^{-4}$. The answer is (D).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_college_mathematics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_medicine.yaml

@@ -46,7 +46,7 @@
   \ monocarbylic acid transporters.\nA: Let's think step by step. We refer to Wikipedia\
   \ articles on medicine for help. Glucose (also known as the blood sugar) is the\
   \ main sugar found in the human body. It is transported into the muscle cell via\
-  \ diffusion through protein transporters called GLUT4. The answer is (A)."
+  \ diffusion through protein transporters called GLUT4. The answer is (A).\n\n"
 "group": "mmlu_flan_cot_fewshot_other"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_college_medicine"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_physics.yaml

@@ -38,7 +38,7 @@
   \ go into the gases internal energy or work done against an external force. However,\
   \ if the volume of the gas container is constant, no work will be done (since work\
   \ is pressure times change in volume). So, at constant volume, all of the heat goes\
-  \ into the internal energy. The answer is (B)."
+  \ into the internal energy. The answer is (B).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_college_physics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_computer_security.yaml

@@ -30,7 +30,7 @@
   \ resulted from improper input validation (due to a missing bounds check) in the\
   \ implementation of the TLS heartbeat extension. The vulnerability was classified\
   \ as a buffer over-read, a situation where more data can be read than should be\
-  \ allowed. The answer is (C)."
+  \ allowed. The answer is (C).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_computer_security"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_conceptual_physics.yaml

@@ -27,7 +27,7 @@
   \ speed in the direction of the wind is greater than it would be in the absence\
   \ of wind, and its direction orthogonal to the wind is the same as it would be in\
   \ the absence of the wind. The total speed, which is these two components added\
-  \ in quadrature, is thus greater than the speed in still air. The answer is (B)."
+  \ in quadrature, is thus greater than the speed in still air. The answer is (B).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_conceptual_physics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_econometrics.yaml

@@ -57,7 +57,7 @@
   \ die away (B) Persist indefinitely (C) Grow exponentially (D) Never occur\nA: Let's\
   \ think step by step. We refer to Wikipedia articles on econometrics for help. This\
   \ is a formal logic problem about stationally process. For a stationary autoregressive\
-  \ process, shocks will eventually die away. The answer is (A)."
+  \ process, shocks will eventually die away. The answer is (A).\n\n"
 "group": "mmlu_flan_cot_fewshot_social_sciences"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_econometrics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_electrical_engineering.yaml

@@ -28,7 +28,7 @@
   \ is 100. Find the total resistance\n(A) 200Ω (B) 100Ω (C) 50Ω (D) 10Ω\nA: Let's\
   \ think step by step. In lap winding, effectively two resistors are connected in\
   \ parallel, so the actual resistance of each pair is 1 Ohm. Since we have 50 pairs,\
-  \ we get a total resistance of 50 Ohms. The answer is (C)."
+  \ we get a total resistance of 50 Ohms. The answer is (C).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_electrical_engineering"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_elementary_mathematics.yaml

@@ -35,7 +35,7 @@
   \nQ: Which expression is equivalent to 5 x 9?\n(A) (5 x 4) x (6 x 5)\n(B) (5 x 5)\
   \ + (5 x 4)\n(C) (5 x 5) + (5 x 9)\n(D) (5 x 9) x (6 x 9)\nA: Let's think step by\
   \ step. We know that 9 = (5 + 4), so 5 x 9 = 5 x (5 + 4) = (5 x 5) + (5 x 4). The\
-  \ answer is (B)."
+  \ answer is (B).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_elementary_mathematics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_formal_logic.yaml

@@ -47,7 +47,7 @@
   \ (∀x)(Px ⊃ ~Dx) → For all x, x is on Mars implies that x do not drive on Mars.\n\
   Option (D): ~Dp: → p do not drive on Mars.\nOf all these options, Option (C) appears\
   \ to be the best and most meaningful interpretation of the argument “No people drive\
-  \ on Mars.” The answer is (C)."
+  \ on Mars.” The answer is (C).\n\n"
 "group": "mmlu_flan_cot_fewshot_humanities"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_formal_logic"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_global_facts.yaml

@@ -28,7 +28,7 @@
   \ of their nation or the world.\nA: Let's think step by step. We refer to Wikipedia\
   \ articles on global facts for help. As of 2019, most people tend to be optimistic\
   \ about their own future but pessimistic about the future of their nation or the\
-  \ world. The answer is (B)."
+  \ world. The answer is (B).\n\n"
 "group": "mmlu_flan_cot_fewshot_other"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_global_facts"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_high_school_biology.yaml

@@ -48,7 +48,7 @@
   \ proceed with cell division. Cues like these act by changing the activity of core\
   \ cell cycle regulators inside the cell. The most common regulators are cyclins\
   \ and cyclin-dependent kinases. Fibroblast cells do not play any role in cell division.\
-  \ The answer is (D)."
+  \ The answer is (D).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_high_school_biology"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_high_school_chemistry.yaml

@@ -44,7 +44,7 @@
   \ (aq) + H_{2}O \nightarrow H_{3}O^{+} + CH3COO^{-}$. The conjugate base is therefore\
   \ the acetate ion. The added strong acid, Nitric acid, will react with the conjugate\
   \ base. Therefore the maximum amount of acid that can be added will be equal to\
-  \ the amount of acetate ion, or 2 moles. The answer is (C)."
+  \ the amount of acetate ion, or 2 moles. The answer is (C).\n\n"
 "group": "mmlu_flan_cot_fewshot_stem"
 "include": "_mmlu_flan_cot_fewshot_template_yaml"
 "task": "mmlu_flan_cot_fewshot_high_school_chemistry"