Merge pull request #922 from EleutherAI/mmlu_subgroups

[Refactor] Mmlu subgroups and weight avg

lm_eval/tasks/mmlu/default/mmlu_us_foreign_policy.yaml

 "dataset_name": "us_foreign_policy"
-"description": "The following are multiple choice questions (with answers) about us foreign policy.\n\n"
+"description": "The following are multiple choice questions (with answers) about us\
+  \ foreign policy.\n\n"
+"group": "mmlu_social_sciences"
+"group_alias": "social_sciences"
 "include": "_default_template_yaml"
 "task": "mmlu_us_foreign_policy"
+"task_alias": "us_foreign_policy"

lm_eval/tasks/mmlu/default/mmlu_virology.yaml

 "dataset_name": "virology"
-"description": "The following are multiple choice questions (with answers) about virology.\n\n"
+"description": "The following are multiple choice questions (with answers) about virology.\n\
+  \n"
+"group": "mmlu_other"
+"group_alias": "other"
 "include": "_default_template_yaml"
 "task": "mmlu_virology"
+"task_alias": "virology"

lm_eval/tasks/mmlu/default/mmlu_world_religions.yaml

 "dataset_name": "world_religions"
-"description": "The following are multiple choice questions (with answers) about world religions.\n\n"
+"description": "The following are multiple choice questions (with answers) about world\
+  \ religions.\n\n"
+"group": "mmlu_humanities"
+"group_alias": "humanities"
 "include": "_default_template_yaml"
 "task": "mmlu_world_religions"
+"task_alias": "world_religions"

lm_eval/tasks/mmlu/flan_cot_fewshot/_mmlu.yaml

+group: mmlu_flan_cot_fewshot
+task:
+  - mmlu_flan_cot_fewshot_stem
+  - mmlu_flan_cot_fewshot_other
+  - mmlu_flan_cot_fewshot_social_sciences
+  - mmlu_flan_cot_fewshot_humanities

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_abstract_algebra.yaml

-dataset_name: abstract_algebra
-description: "The following are multiple choice questions (with answers) about abstract\
+"dataset_name": "abstract_algebra"
+"description": "The following are multiple choice questions (with answers) about abstract\
   \ algebra.\n\nQ: Statement 1 | Every element of a group generates a cyclic subgroup\
   \ of the group. Statement 2 | The symmetric group S_10 has 10 elements.\n(A) True,\
   \ True (B) False, False (C) True, False (D) False, True\nA: Let's think step by\
@@ -36,5 +36,6 @@ description: "The following are multiple choice questions (with answers) about a
   \ x = 2, hence x^2 + 1 does not have any roots. For c = 2 the polynomial x^2 + 2\
   \ has two roots at x = 1 and x = 2. Hence Z_3[x]/(x^2 + c) is a field if and only\
   \ if c = 1. The answer is (B)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_abstract_algebra
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_abstract_algebra"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_anatomy.yaml

-dataset_name: anatomy
-description: "The following are multiple choice questions (with answers) about anatomy.\n\
+"dataset_name": "anatomy"
+"description": "The following are multiple choice questions (with answers) about anatomy.\n\
   \nQ: Which of the following is the body cavity that contains the pituitary gland?\n\
   (A) Abdominal (B) Cranial (C) Pleural (D) Spinal\nA: Let's think step by step. We\
-  \ refer to Wikipedia articles on anatomy for help. Let\u2019s solve this problem\
-  \ step by step. The pituitary gland is the major endocrine gland attached to the\
-  \ base of the brain, and it is contained in the Cranial cavity. The answer is (B).\n\
-  \nQ: Which of these branches of the trigeminal nerve contain somatic motor processes?\n\
+  \ refer to Wikipedia articles on anatomy for help. Let’s solve this problem step\
+  \ by step. The pituitary gland is the major endocrine gland attached to the base\
+  \ of the brain, and it is contained in the Cranial cavity. The answer is (B).\n\n\
+  Q: Which of these branches of the trigeminal nerve contain somatic motor processes?\n\
   (A) The supraorbital nerve (B) The infraorbital nerve (C) The mental nerve (D) None\
   \ of the above\nA: Let's think step by step. We refer to Wikipedia articles on anatomy\
-  \ for help. Let\u2019s solve this problem step by step. \nWe know the following:\
-  \ (A) The supraorbital nerve (also known as the frontal nerve) is the largest branch\
+  \ for help. Let’s solve this problem step by step. \nWe know the following: (A)\
+  \ The supraorbital nerve (also known as the frontal nerve) is the largest branch\
   \ of the ophthalmic nerve and branch of ophthalmic division of the trigeminal nerve.\
   \ (B) The infraorbital nerve is a branch of the maxillary division of the trigeminal\
   \ nerve. (C) The mental nerve is a branch of the mandibular division of the trigeminal\
@@ -19,39 +19,39 @@ description: "The following are multiple choice questions (with answers) about a
   (A) excess overbite of the upper lateral incisors. (B) negative overjet of the upper\
   \ central incisors. (C) excess overjet of the upper lateral incisors. (D) excess\
   \ overjet of the upper central incisors.\nA: Let's think step by step. We refer\
-  \ to Wikipedia articles on anatomy for help. Let\u2019s solve this problem step\
-  \ by step. This is a question related to anatomy and orthodontics. Excess overjet\
-  \ is associated with Class II occlusions; therefore, we can safely eliminate (B)\
-  \ from the list, as negative overjet is often associated with Class III occlusions.\
-  \ Now, we need to determine the location of the excess overjet, and that would be\
-  \ the upper (maxillary) lateral incisors. Only (C) has the correct information.\
-  \ The answer is (C).\n\nQ: The pleura\n(A) have no sensory innervation. (B) are\
-  \ separated by a 2 mm space. (C) extend into the neck. (D) are composed of respiratory\
-  \ epithelium.\nA: Let's think step by step. We refer to Wikipedia articles on anatomy\
-  \ for help. Let\u2019s solve this problem step by step. First, recall that the pleura\
-  \ refers to the thin layer of tissue that covers the lungs and lines the interior\
-  \ wall of the chest cavity. Now, let\u2019s look at each option:\nOption (A): \u201C\
-  The pleura have no sensory innervation.\u201D This information is not correct. The\
-  \ pleura do have a sensory innervation.\nOption (B): \u201CThe pleura are separated\
-  \ by a 2 mm space.\u201D This information is not correct. There is a very thin \u201C\
-  potential\u201D space between the layers of the pleura; however, it is typically\
-  \ filled with serous pleural fluid. \nOption (C): \u201CThe pleura extend into the\
-  \ neck.\u201D This information is actuakky true. The cervical pleura, also known\
-  \ as the dome of the pleuradome of the pleura, lines the extendsiton of the pleural\
-  \ cavity into the neck.\nOption (D): \u201CThe pleura are composed of respiratory\
-  \ epithelium.\u201D This information is not correct. The pleaura are composed of\
-  \ connective tissue (CT).\nBecause (A), (B), and (D) are all incorrect, (D) is the\
-  \ only correct answer. The answer is (C).\n\nQ: What is the embryological origin\
+  \ to Wikipedia articles on anatomy for help. Let’s solve this problem step by step.\
+  \ This is a question related to anatomy and orthodontics. Excess overjet is associated\
+  \ with Class II occlusions; therefore, we can safely eliminate (B) from the list,\
+  \ as negative overjet is often associated with Class III occlusions. Now, we need\
+  \ to determine the location of the excess overjet, and that would be the upper (maxillary)\
+  \ lateral incisors. Only (C) has the correct information. The answer is (C).\n\n\
+  Q: The pleura\n(A) have no sensory innervation. (B) are separated by a 2 mm space.\
+  \ (C) extend into the neck. (D) are composed of respiratory epithelium.\nA: Let's\
+  \ think step by step. We refer to Wikipedia articles on anatomy for help. Let’s\
+  \ solve this problem step by step. First, recall that the pleura refers to the thin\
+  \ layer of tissue that covers the lungs and lines the interior wall of the chest\
+  \ cavity. Now, let’s look at each option:\nOption (A): “The pleura have no sensory\
+  \ innervation.” This information is not correct. The pleura do have a sensory innervation.\n\
+  Option (B): “The pleura are separated by a 2 mm space.” This information is not\
+  \ correct. There is a very thin “potential” space between the layers of the pleura;\
+  \ however, it is typically filled with serous pleural fluid. \nOption (C): “The\
+  \ pleura extend into the neck.” This information is actuakky true. The cervical\
+  \ pleura, also known as the dome of the pleuradome of the pleura, lines the extendsiton\
+  \ of the pleural cavity into the neck.\nOption (D): “The pleura are composed of\
+  \ respiratory epithelium.” This information is not correct. The pleaura are composed\
+  \ of connective tissue (CT).\nBecause (A), (B), and (D) are all incorrect, (D) is\
+  \ the only correct answer. The answer is (C).\n\nQ: What is the embryological origin\
   \ of the hyoid bone?\n(A) The first pharyngeal arch (B) The first and second pharyngeal\
   \ arches (C) The second pharyngeal arch (D) The second and third pharyngeal arches\n\
   A: Let's think step by step. We refer to Wikipedia articles on anatomy for help.\
-  \ Let\u2019s solve this problem step by step. The hyoid bone, which is also known\
-  \ as the hyooid, is a a small U-shaped bone located in the anterior neck. In its\
-  \ resting position, it lies between the ase of the mandible and the third cervical\
-  \ vertebrae. We know that the second and the third pharyngeal arches give rise to\
-  \ the horns of the hyoid bone; therefore, the embryological origin of the hyoid\
-  \ bone are the second and the third pharyngeal arches\u2014this information is covered\
-  \ in the last option (D). Therefore, we conclude that (D) must be the correct answer.\
-  \ The answer is (D)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_anatomy
+  \ Let’s solve this problem step by step. The hyoid bone, which is also known as\
+  \ the hyooid, is a a small U-shaped bone located in the anterior neck. In its resting\
+  \ position, it lies between the ase of the mandible and the third cervical vertebrae.\
+  \ We know that the second and the third pharyngeal arches give rise to the horns\
+  \ of the hyoid bone; therefore, the embryological origin of the hyoid bone are the\
+  \ second and the third pharyngeal arches—this information is covered in the last\
+  \ option (D). Therefore, we conclude that (D) must be the correct answer. The answer\
+  \ is (D)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_anatomy"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_astronomy.yaml

-dataset_name: astronomy
-description: "The following are multiple choice questions (with answers) about astronomy.\n\
+"dataset_name": "astronomy"
+"description": "The following are multiple choice questions (with answers) about astronomy.\n\
   \nQ: Where do most short-period comets come from and how do we know?\n(A) The Kuiper\
   \ belt; short period comets tend to be in the plane of the solar system just like\
   \ the Kuiper belt. (B) The Kuiper belt; short period comets tend to come from random\
@@ -16,39 +16,40 @@ description: "The following are multiple choice questions (with answers) about a
   \ lighter on Mars. (C) It would be harder since the truck is lighter on Mars. (D)\
   \ It would be the same no matter where you are.\nA: Let's think step by step. If\
   \ we assume that there is no friction, the force needed to accelerate the truck\
-  \ is by Newton\u2019s second law only dependent on the mass of the truck. Hence\
-  \ (A), (B) and (C) are incorrect since it doesn\u2019t matter that it\u2019s on\
-  \ Mars, and (D) is the correct answer. The answer is (D).\n\nQ: Say the pupil of\
-  \ your eye has a diameter of 5 mm and you have a telescope with an aperture of 50\
-  \ cm. How much more light can the telescope gather than your eye?\n(A) 10000 times\
-  \ more (B) 100 times more (C) 1000 times more (D) 10 times more\nA: Let's think\
-  \ step by step. The amount of light is proportional to the aperture area $A = \\\
-  pi D^2/4$ for a lens with diameter $D$, so the relative amounts of light between\
-  \ the eye with diameter 5mm and the telescope with diameter 50mm is $(50 cm)^2/(5mm)^2\
-  \ = 10000$. The answer is (A).\n\nQ: Why isn't there a planet where the asteroid\
-  \ belt is located?\n(A) A planet once formed here but it was broken apart by a catastrophic\
-  \ collision. (B) There was not enough material in this part of the solar nebula\
-  \ to form a planet. (C) There was too much rocky material to form a terrestrial\
-  \ planet but not enough gaseous material to form a jovian planet. (D) Resonance\
-  \ with Jupiter prevented material from collecting together to form a planet.\nA:\
-  \ Let's think step by step. The asteroid belt is a stellar disc consisting of a\
-  \ large number of asteroids between Mars and Jupiter's orbits. The asteroids in\
-  \ this belt are affected by the gravitational pull from both other asteroids and\
-  \ nearby planets. Due to the strong gravitational force of Jupiter there are resonances\
-  \ that give rise to low density regions of asteroids known as the Kirkwood gap.\
-  \ So (B) and (C) are not correct since it\u2019s not a lack of material that prevents\
-  \ a planet from being formed, and (A) is incorrect because the Kirkwood gap would\
-  \ have prevented a planet from forming in the first place, and (D) is the correct\
-  \ option. The answer is (D).\n\nQ: Why is Mars red?\n(A) Because the surface is\
-  \ covered with heavily oxidized (\"rusted\") minerals. (B) Because the atmosphere\
-  \ scatters more light at bluer wavelengths transmitting mostly red light. (C) Because\
-  \ Mars is covered with ancient lava flows which are red in color. (D) Because flowing\
-  \ water on Mars's surface altered the surface minerals several billion years ago.\n\
-  A: Let's think step by step. Option (B) is not correct because if the red color\
-  \ was caused by the scattering off the atmosphere, then the earth with a much thicker\
-  \ atmosphere would also look red. Options (C) and (D) are not specific enough about\
-  \ why the color of the surface would be red, while (A) is correct because it explains\
-  \ that the surface is red due to the rusted materials on the surface and the red\
-  \ color comes from the rust. So the correct option is (A). The answer is (A)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_astronomy
+  \ is by Newton’s second law only dependent on the mass of the truck. Hence (A),\
+  \ (B) and (C) are incorrect since it doesn’t matter that it’s on Mars, and (D) is\
+  \ the correct answer. The answer is (D).\n\nQ: Say the pupil of your eye has a diameter\
+  \ of 5 mm and you have a telescope with an aperture of 50 cm. How much more light\
+  \ can the telescope gather than your eye?\n(A) 10000 times more (B) 100 times more\
+  \ (C) 1000 times more (D) 10 times more\nA: Let's think step by step. The amount\
+  \ of light is proportional to the aperture area $A = \\pi D^2/4$ for a lens with\
+  \ diameter $D$, so the relative amounts of light between the eye with diameter 5mm\
+  \ and the telescope with diameter 50mm is $(50 cm)^2/(5mm)^2 = 10000$. The answer\
+  \ is (A).\n\nQ: Why isn't there a planet where the asteroid belt is located?\n(A)\
+  \ A planet once formed here but it was broken apart by a catastrophic collision.\
+  \ (B) There was not enough material in this part of the solar nebula to form a planet.\
+  \ (C) There was too much rocky material to form a terrestrial planet but not enough\
+  \ gaseous material to form a jovian planet. (D) Resonance with Jupiter prevented\
+  \ material from collecting together to form a planet.\nA: Let's think step by step.\
+  \ The asteroid belt is a stellar disc consisting of a large number of asteroids\
+  \ between Mars and Jupiter's orbits. The asteroids in this belt are affected by\
+  \ the gravitational pull from both other asteroids and nearby planets. Due to the\
+  \ strong gravitational force of Jupiter there are resonances that give rise to low\
+  \ density regions of asteroids known as the Kirkwood gap. So (B) and (C) are not\
+  \ correct since it’s not a lack of material that prevents a planet from being formed,\
+  \ and (A) is incorrect because the Kirkwood gap would have prevented a planet from\
+  \ forming in the first place, and (D) is the correct option. The answer is (D).\n\
+  \nQ: Why is Mars red?\n(A) Because the surface is covered with heavily oxidized\
+  \ (\"rusted\") minerals. (B) Because the atmosphere scatters more light at bluer\
+  \ wavelengths transmitting mostly red light. (C) Because Mars is covered with ancient\
+  \ lava flows which are red in color. (D) Because flowing water on Mars's surface\
+  \ altered the surface minerals several billion years ago.\nA: Let's think step by\
+  \ step. Option (B) is not correct because if the red color was caused by the scattering\
+  \ off the atmosphere, then the earth with a much thicker atmosphere would also look\
+  \ red. Options (C) and (D) are not specific enough about why the color of the surface\
+  \ would be red, while (A) is correct because it explains that the surface is red\
+  \ due to the rusted materials on the surface and the red color comes from the rust.\
+  \ So the correct option is (A). The answer is (A)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_astronomy"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_business_ethics.yaml

-dataset_name: business_ethics
-description: "The following are multiple choice questions (with answers) about business\
+"dataset_name": "business_ethics"
+"description": "The following are multiple choice questions (with answers) about business\
   \ ethics.\n\nQ: In contrast to _______, _______ aim to reward favourable behaviour\
   \ by companies. The success of such campaigns have been heightened through the use\
   \ of ___________, which allow campaigns to facilitate the company in achieving _________\
@@ -7,12 +7,12 @@ description: "The following are multiple choice questions (with answers) about b
   \ Boycotts, Digital technology, Increased Sales (C) Boycotts, Buyalls, Blockchain\
   \ technology, Charitable donations (D) Boycotts, Buycotts, Digital technology, Increased\
   \ Sales\nA: Let's think step by step. We refer to Wikipedia articles on business\
-  \ ethics for help. The sentence that best uses the possible options above is \u201C\
-  In contrast to *boycotts*, *buycotts* aim to reward favourable behavior by companies.\
+  \ ethics for help. The sentence that best uses the possible options above is “In\
+  \ contrast to *boycotts*, *buycotts* aim to reward favourable behavior by companies.\
   \ The success of such campaigns have been heightened through the use of *digital\
   \ technology*, which allow campaigns to facilitate the company in achieving *increased\
-  \ sales*.\u201D The answer is (D).\n\nQ: _______ is the direct attempt to formally\
-  \ or informally manage ethical issues or problems, through specific policies, practices\
+  \ sales*.” The answer is (D).\n\nQ: _______ is the direct attempt to formally or\
+  \ informally manage ethical issues or problems, through specific policies, practices\
   \ and programmes.\n(A) Corporate social responsibility (B) Business ethics management\
   \ (C) Sustainability (D) Environmental management\nA: Let's think step by step.\
   \ We refer to Wikipedia articles on business ethics for help. The direct attempt\
@@ -26,30 +26,31 @@ description: "The following are multiple choice questions (with answers) about b
   \ action, Violent direct action, Non-violent direct-action Boycott (D) Non-violent\
   \ direct action, Instrumental action, Indirect action, Information campaign\nA:\
   \ Let's think step by step. We refer to Wikipedia articles on business ethics for\
-  \ help. The sentence that best uses the possible options above is \u201CThree contrasting\
+  \ help. The sentence that best uses the possible options above is “Three contrasting\
   \ tactics that CSO's can engage in to meet their aims are *indirect action*, which\
   \ typically involves research and communication, *violent direct action*, which\
   \ may involve physically attacking a company's operations or *non-violent direct\
-  \ action*, often involving some form of *boycott*.\u201D The answer is (C).\n\n\
-  Q: To ensure the independence of the non-executive board members, there are a number\
+  \ action*, often involving some form of *boycott*.” The answer is (C).\n\nQ: To\
+  \ ensure the independence of the non-executive board members, there are a number\
   \ of steps which can be taken, which include non-executives being drawn from _______\
   \ the company, being appointed for a _________ time period as well as being appointed\
   \ _________.\n(A) Outside, Limited, Independently (B) Inside, Limited, Intermittently\
   \ (C) Outside, Unlimited, Intermittently (D) Inside, Unlimited, Independently\n\
   A: Let's think step by step. We refer to Wikipedia articles on business ethics for\
-  \ help. The sentence that best uses the possible options above is \u201CTo ensure\
-  \ the independence of the non-executive board members, there are a number of steps\
-  \ which can be taken, which include non-executives being draw from *outside* the\
-  \ company, being appointed for a *limited* time period as well as being imported\
-  \ *independently*. The answer is (A).\n\nQ: Beyond the business case for engaging\
-  \ in CSR there are a number of moral arguments relating to: negative _______, the\
-  \ _______that corporations possess and the ________ of business and society.\n(A)\
-  \ Externalities, Power, Independence (B) Publicity, Insubstantial resources, Mutual\
-  \ dependence (C) Publicity, Power, Independence (D) Externalities, Power, Mutual\
-  \ dependence\nA: Let's think step by step. We refer to Wikipedia articles on business\
-  \ ethics for help. The sentence that best uses the possible options above is \u201C\
-  Beyond the business case for engaging the CSR there are a number of moral arguments\
-  \ relating to: negative *externalities*, the *power* that corporations possess and\
-  \ the *mutual independence* of business and society. The answer is (D)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_business_ethics
+  \ help. The sentence that best uses the possible options above is “To ensure the\
+  \ independence of the non-executive board members, there are a number of steps which\
+  \ can be taken, which include non-executives being draw from *outside* the company,\
+  \ being appointed for a *limited* time period as well as being imported *independently*.\
+  \ The answer is (A).\n\nQ: Beyond the business case for engaging in CSR there are\
+  \ a number of moral arguments relating to: negative _______, the _______that corporations\
+  \ possess and the ________ of business and society.\n(A) Externalities, Power, Independence\
+  \ (B) Publicity, Insubstantial resources, Mutual dependence (C) Publicity, Power,\
+  \ Independence (D) Externalities, Power, Mutual dependence\nA: Let's think step\
+  \ by step. We refer to Wikipedia articles on business ethics for help. The sentence\
+  \ that best uses the possible options above is “Beyond the business case for engaging\
+  \ the CSR there are a number of moral arguments relating to: negative *externalities*,\
+  \ the *power* that corporations possess and the *mutual independence* of business\
+  \ and society. The answer is (D)."
+"group": "mmlu_flan_cot_fewshot_other"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_business_ethics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_clinical_knowledge.yaml

-dataset_name: clinical_knowledge
-description: 'The following are multiple choice questions (with answers) about clinical
-  knowledge.
-
-
-  Q: Glycolysis is the name given to the pathway involving the conversion of:
-
-  (A) glycogen to glucose-1-phosphate. (B) glycogen or glucose to fructose. (C) glycogen
-  or glucose to pyruvate or lactate. (D) glycogen or glucose to pyruvate or acetyl
-  CoA.
-
-  A: Let''s think step by step. We refer to Wikipedia articles on clinical knowledge
-  for help. Glycolysis is the name given to the pathway involving conversion of glycogen
-  or glucose to pyruvate or lactate. The answer is (C).
-
-
-  Q: What is the difference between a male and a female catheter?
-
-  (A) Male and female catheters are different colours. (B) Male catheters are longer
-  than female catheters. (C) Male catheters are bigger than female catheters. (D)
-  Female catheters are longer than male catheters.
-
-  A: Let''s think step by step. We refer to Wikipedia articles on clinical knowledge
-  for help. The difference between a male and female catheter is that male catheters
-  tend to be longer than female catheters. The answer is (B).
-
-
-  Q: How many attempts should you make to cannulate a patient before passing the job
-  on to a senior colleague, according to the medical knowledge of 2020?
-
-  (A) 4 (B) 3 (C) 2 (D) 1
-
-  A: Let''s think step by step. We refer to Wikipedia articles on clinical knowledge
-  for help. According to the medical protocol as of 2020, you should make two attempts
-  to cannulate a patient before passing the job on to a more-senior practitioner.
-  The answer is (C).
-
-
-  Q: In the assessment of the hand function which of the following is true?
-
-  (A) Abduction of the thumb is supplied by spinal root T2 (B) Opposition of the thumb
-  by opponens policis is supplied by spinal root T1 (C) Finger adduction is supplied
-  by the median nerve (D) Finger abduction is mediated by the palmar interossei
-
-  A: Let''s think step by step. We refer to Wikipedia articles on clinical knowledge
-  for help. Of all the options, it is only true that the opposition of the thumb by
-  opponens pollicis is supplied by spinal root T1. The answer is (B).
-
-
-  Q: The energy for all forms of muscle contraction is provided by:
-
-  (A) ATP. (B) ADP. (C) phosphocreatine. (D) oxidative phosphorylation.
-
-  A: Let''s think step by step. We refer to Wikipedia articles on clinical knowledge
-  for help. The energy for muscular contraction is provided by ATP (adenosine triphosphate),
-  which is the powerhouse of the cell. The answer is (A).'
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_clinical_knowledge
+"dataset_name": "clinical_knowledge"
+"description": "The following are multiple choice questions (with answers) about clinical\
+  \ knowledge.\n\nQ: Glycolysis is the name given to the pathway involving the conversion\
+  \ of:\n(A) glycogen to glucose-1-phosphate. (B) glycogen or glucose to fructose.\
+  \ (C) glycogen or glucose to pyruvate or lactate. (D) glycogen or glucose to pyruvate\
+  \ or acetyl CoA.\nA: Let's think step by step. We refer to Wikipedia articles on\
+  \ clinical knowledge for help. Glycolysis is the name given to the pathway involving\
+  \ conversion of glycogen or glucose to pyruvate or lactate. The answer is (C).\n\
+  \nQ: What is the difference between a male and a female catheter?\n(A) Male and\
+  \ female catheters are different colours. (B) Male catheters are longer than female\
+  \ catheters. (C) Male catheters are bigger than female catheters. (D) Female catheters\
+  \ are longer than male catheters.\nA: Let's think step by step. We refer to Wikipedia\
+  \ articles on clinical knowledge for help. The difference between a male and female\
+  \ catheter is that male catheters tend to be longer than female catheters. The answer\
+  \ is (B).\n\nQ: How many attempts should you make to cannulate a patient before\
+  \ passing the job on to a senior colleague, according to the medical knowledge of\
+  \ 2020?\n(A) 4 (B) 3 (C) 2 (D) 1\nA: Let's think step by step. We refer to Wikipedia\
+  \ articles on clinical knowledge for help. According to the medical protocol as\
+  \ of 2020, you should make two attempts to cannulate a patient before passing the\
+  \ job on to a more-senior practitioner. The answer is (C).\n\nQ: In the assessment\
+  \ of the hand function which of the following is true?\n(A) Abduction of the thumb\
+  \ is supplied by spinal root T2 (B) Opposition of the thumb by opponens policis\
+  \ is supplied by spinal root T1 (C) Finger adduction is supplied by the median nerve\
+  \ (D) Finger abduction is mediated by the palmar interossei\nA: Let's think step\
+  \ by step. We refer to Wikipedia articles on clinical knowledge for help. Of all\
+  \ the options, it is only true that the opposition of the thumb by opponens pollicis\
+  \ is supplied by spinal root T1. The answer is (B).\n\nQ: The energy for all forms\
+  \ of muscle contraction is provided by:\n(A) ATP. (B) ADP. (C) phosphocreatine.\
+  \ (D) oxidative phosphorylation.\nA: Let's think step by step. We refer to Wikipedia\
+  \ articles on clinical knowledge for help. The energy for muscular contraction is\
+  \ provided by ATP (adenosine triphosphate), which is the powerhouse of the cell.\
+  \ The answer is (A)."
+"group": "mmlu_flan_cot_fewshot_other"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_clinical_knowledge"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_biology.yaml

-dataset_name: college_biology
-description: "The following are multiple choice questions (with answers) about college\
+"dataset_name": "college_biology"
+"description": "The following are multiple choice questions (with answers) about college\
   \ biology.\n\nQ: Which of the following represents an accurate statement concerning\
   \ arthropods?\n(A) They possess an exoskeleton composed primarily of peptidoglycan.\
   \ (B) They possess an open circulatory system with a dorsal heart. (C) They are\
@@ -19,7 +19,7 @@ description: "The following are multiple choice questions (with answers) about c
   \ Law, $p^2 + 2 p q + q^2 = 1$, and $p + q = 1$ where $p$ is the frequency of the\
   \ dominant allele, $q$ is the frequency of the recessive allele, and $p^2$, $q^2$,\
   \ and $2pq$ are the frequencies of dominant homozygous, recessive homozygous, and\
-  \ heterozygous individuals, respectively. \u200BThe frequency of the recessive allele\
+  \ heterozygous individuals, respectively. ​The frequency of the recessive allele\
   \ (q) is $\\sqrt{\frac{1}{400}} = 0.05$. We have $p = 1 - q = 0.95$. The frequency\
   \ of heterozygous individuals is $2pq = 2 \\cdot 0.05 \\cdot 0.95 = 0.095$. The\
   \ number of heterozygous individuals is equal to the frequency of heterozygous individuals\
@@ -56,5 +56,6 @@ description: "The following are multiple choice questions (with answers) about c
   \ the human and bird forearms, which rules out (D). Humans and birds do belong to\
   \ the same clade - a group of organisms composed of a common ancestor. The answer\
   \ is (C)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_college_biology
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_college_biology"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_chemistry.yaml

-dataset_name: college_chemistry
-description: "The following are multiple choice questions (with answers) about college\
-  \ chemistry.\n\nQ: 3 Cl\u2212(aq) + 4 CrO_4^2\u2212(aq) + 23 H+(aq) \u2192 3 HClO2(aq)\
-  \ + 4 Cr3+(aq) + 10 H2O(l). In the reaction shown above, Cl\u2212(aq) behaves as\n\
-  (A) an acid (B) a base (C) a catalyst (D) a reducing agent\nA: Let's think step\
-  \ by step. A molecule that behaves as a base accepts an H+ ion (or proton) from\
-  \ another molecule, whereas a molecule that behaves as an acid donates an H+ ion\
-  \ (or proton) to another molecule. Neither of these is the case for Cl in this reaction,\
-  \ which rules out (A) and (B). A catalyst is a substance that only accelerates a\
-  \ reaction without itself undergoing chemical change, which is not the case here.\
-  \ This rules out (C). Instead, the $Cl^{-} molecules carry a negative charge, which\
-  \ they donate in the reaction to form 3 HClO2. This is the behavior of a reducing\
-  \ agent, or (D). The answer is (D).\n\nQ: Which of the following statements about\
-  \ the lanthanide elements is NOT true?\n(A) The most common oxidation state for\
-  \ the lanthanide elements is +3. (B) Lanthanide complexes often have high coordination\
-  \ numbers (> 6). (C) All of the lanthanide elements react with aqueous acid to liberate\
-  \ hydrogen. (D) The atomic radii of the lanthanide elements increase across the\
-  \ period from La to Lu.\nA: Let's think step by step. The atomic radii of the lanthanide\
-  \ elements in fact decrease across the period from La to Lu. Options (A), (B), and\
-  \ (C) are all true. This means that only (D) is NOT true. The answer is (D).\n\n\
-  Q: Which of the following lists the hydrides of group-14 elements in order of thermal\
-  \ stability, from lowest to highest?\n(A) PbH4 < SnH4 < GeH4 < SiH4 < CH4 (B) PbH4\
-  \ < SnH4 < CH4 < GeH4 < SiH4 (C) CH4 < SiH4 < GeH4 < SnH4 < PbH4 (D) CH4 < PbH4\
-  \ < GeH4 < SnH4 < SiH4\nA: Let's think step by step. The thermal stability of group-14\
-  \ hydrides decreases as we move from the top of group 14 to the bottom. The order\
-  \ of elements in the group from top to bottom is C, Si, Ge, Sn, Pb. Therefore in\
-  \ order of increasing thermal stability we have PbH4, SnH4, GeH4, SiH4, and CH4,\
-  \ or answer (A). The answer is (A).\n\nQ: Predict the number of lines in the EPR\
-  \ spectrum of a solution of 13C-labelled methyl radical (13CH3\u2022), assuming\
-  \ the lines do not overlap.\n(A) 4 (B) 3 (C) 6 (D) 24 (E) 8\nA: Let's think step\
-  \ by step. The electron paramagnetic resonance spectrum will be split by two forms\
-  \ of interactions. The first is the hyperfine interaction with the 13C (nuclear\
-  \ spin $I = \nrac{1}{2}$) which will split the spectrum into 2 lines. This will\
-  \ be further split into 4 lines by the interaction with three equivalent 1H nuclei.\
-  \ The total number of lines is therefore $2 \\cdot 4 = 8$. The answer is (E)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_college_chemistry
+"dataset_name": "college_chemistry"
+"description": "The following are multiple choice questions (with answers) about college\
+  \ chemistry.\n\nQ: 3 Cl−(aq) + 4 CrO_4^2−(aq) + 23 H+(aq) → 3 HClO2(aq) + 4 Cr3+(aq)\
+  \ + 10 H2O(l). In the reaction shown above, Cl−(aq) behaves as\n(A) an acid (B)\
+  \ a base (C) a catalyst (D) a reducing agent\nA: Let's think step by step. A molecule\
+  \ that behaves as a base accepts an H+ ion (or proton) from another molecule, whereas\
+  \ a molecule that behaves as an acid donates an H+ ion (or proton) to another molecule.\
+  \ Neither of these is the case for Cl in this reaction, which rules out (A) and\
+  \ (B). A catalyst is a substance that only accelerates a reaction without itself\
+  \ undergoing chemical change, which is not the case here. This rules out (C). Instead,\
+  \ the $Cl^{-} molecules carry a negative charge, which they donate in the reaction\
+  \ to form 3 HClO2. This is the behavior of a reducing agent, or (D). The answer\
+  \ is (D).\n\nQ: Which of the following statements about the lanthanide elements\
+  \ is NOT true?\n(A) The most common oxidation state for the lanthanide elements\
+  \ is +3. (B) Lanthanide complexes often have high coordination numbers (> 6). (C)\
+  \ All of the lanthanide elements react with aqueous acid to liberate hydrogen. (D)\
+  \ The atomic radii of the lanthanide elements increase across the period from La\
+  \ to Lu.\nA: Let's think step by step. The atomic radii of the lanthanide elements\
+  \ in fact decrease across the period from La to Lu. Options (A), (B), and (C) are\
+  \ all true. This means that only (D) is NOT true. The answer is (D).\n\nQ: Which\
+  \ of the following lists the hydrides of group-14 elements in order of thermal stability,\
+  \ from lowest to highest?\n(A) PbH4 < SnH4 < GeH4 < SiH4 < CH4 (B) PbH4 < SnH4 <\
+  \ CH4 < GeH4 < SiH4 (C) CH4 < SiH4 < GeH4 < SnH4 < PbH4 (D) CH4 < PbH4 < GeH4 <\
+  \ SnH4 < SiH4\nA: Let's think step by step. The thermal stability of group-14 hydrides\
+  \ decreases as we move from the top of group 14 to the bottom. The order of elements\
+  \ in the group from top to bottom is C, Si, Ge, Sn, Pb. Therefore in order of increasing\
+  \ thermal stability we have PbH4, SnH4, GeH4, SiH4, and CH4, or answer (A). The\
+  \ answer is (A).\n\nQ: Predict the number of lines in the EPR spectrum of a solution\
+  \ of 13C-labelled methyl radical (13CH3•), assuming the lines do not overlap.\n\
+  (A) 4 (B) 3 (C) 6 (D) 24 (E) 8\nA: Let's think step by step. The electron paramagnetic\
+  \ resonance spectrum will be split by two forms of interactions. The first is the\
+  \ hyperfine interaction with the 13C (nuclear spin $I = \nrac{1}{2}$) which will\
+  \ split the spectrum into 2 lines. This will be further split into 4 lines by the\
+  \ interaction with three equivalent 1H nuclei. The total number of lines is therefore\
+  \ $2 \\cdot 4 = 8$. The answer is (E)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_college_chemistry"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_computer_science.yaml

-dataset_name: college_computer_science
-description: 'The following are multiple choice questions (with answers) about college
-  computer science.
-
-
-  Q: Which of the following regular expressions is equivalent to (describes the same
-  set of strings as) (a* + b)*(c + d)?
-
-  (A) a*(c + d)+ b(c + d)
-
-  (B) a*(c + d)* + b(c + d)*
-
-  (C) a*(c + d)+ b*(c + d)
-
-  (D) (a + b)*c +(a + b)*d
-
-  A: Let''s think step by step. We know that:
-
-  1. (X* + Y)* = (X + Y)*
-
-  2. X(Y + Z)? = XY + XZ
-
-  Using equation 1 we can rewrite (a* + b)*(c + d)? as:
-
-  3. (a + b)*(c + d)?
-
-  Using equation 2 we can rewrite equation 3 as:
-
-  (a + b)*c + (a + b)*d The answer is (D).
-
-
-  Q: The Singleton design pattern is used to guarantee that only a single instance
-  of a class may be instantiated. Which of the following is (are) true of this design
-  pattern?
-
-  I. The Singleton class has a static factory method to provide its instance.
-
-  II. The Singleton class can be a subclass of another class.
-
-  III. The Singleton class has a private constructor.
-
-  (A) I only
-
-  (B) II only
-
-  (C) III only
-
-  (D) I, II, and III
-
-  A: Let''s think step by step. Statement I is a correct statement about a Singleton,
-  because a Singleton restricts instantiation to a single, static method. Statement
-  II is also correct, because there is no inherent restriction regarding the inheritance
-  of a Singleton. Statement III is also correct, because a Singletons must be instantiated
-  only once, so its constructor is made private to prevent any construction except
-  via its static factory method.
-
-  Given these facts, statements I, II, and III are all correct. The answer is (D).
-
-
-  Q: A certain pipelined RISC machine has 8 general-purpose registers R0, R1, . .
-  . , R7 and supports the following operations:
-
-  ADD Rs1, Rs2, Rd (Add Rs1 to Rs2 and put the sum in Rd)
-
-  MUL Rs1, Rs2, Rd (Multiply Rs1 by Rs2 and put the product in Rd)
-
-  An operation normally takes one cycle; however, an operation takes two cycles if
-  it produces a result required by the immediately following operation in an operation
-  sequence.
-
-  Consider the expression AB + ABC + BC, where variables A, B, C are located in registers
-  R0, R1, R2. If the contents of these three registers must not be modified, what
-  is the minimum number of clock cycles required for an operation sequence that computes
-  the value of AB + ABC + BC?
-
-  (A) 5 (B) 6 (C) 7 (D) 8
-
-  A: Let''s think step by step. First, we are given that A is in R0, B is in R1, and
-  C is in R2.
-
-  Next, we can see that we must compute three multiplies (AB, BC, and ABC) and two
-  adds (AB + ABC, (AB + ABC) + BC) to compute our final answer, resulting in a minimum
-  of five clock cycles.
-
-  Next, we can see that there is no way to avoid at least one pipeline stall when
-  computing our final answer, because to compute our final sum we must wait at least
-  one cycle for the results from the previous stage to be ready. Thus, our minimum
-  number of cycles must be 6.
-
-  We can verify that we can create a solution that requires only six cycles as follows:
-
-  compute AB: MUL R0, R1, R3
-
-  compute BC: MUL R1, R2, R4
-
-  compute ABC: MUL R3, R4, R5
-
-  compute AB + BC: ADD R3, R4, R6
-
-  STALL
-
-  compute AB + ABC + BC: ADD R5, R6, R7
-
-  So there are 6 cycles. The answer is (B).
-
-
-  Q: A compiler generates code for the following assignment statement.
-
-  G := (A + B) * C - (D + E) * F
-
-  The target machine has a single accumulator and a single-address instruction set
-  consisting of instructions load, store, add, subtract, and multiply. For the arithmetic
-  operations, the left operand is taken from the accumulator and the result appears
-  in the accumulator. The smallest possible number of instructions in the resulting
-  code is
-
-  (A) 5 (B) 6 (C) 7 (D) 9
-
-  A: Let''s think step by step. We can compute the final answer with the following
-  sequence of operations:
-
-  1. LOAD D  (accumulator = D)
-
-  2. ADD E  (accumulator = D+E)
-
-  3. MUL F  (accumulator = (D+E)*F)
-
-  4. STORE X (X = (D+E)*F)
-
-  5. LOAD A  (accumulator = A)
-
-  6. ADD B  (accumulator = A+B)
-
-  7. MUL C  (accumulator = (A+B)*C)
-
-  8. SUB X  (accumulator = (A+B)*C - (D+E)*F)
-
-  9. STORE G (G = (A+B)*C - (D+E)*F)
-
-  This sequence takes 9 instructions. The answer is (D).
-
-
-  Q: Consider a computer design in which multiple processors, each with a private
-  cache memory, share global memory using a single bus. This bus is the critical system
-  resource. Each processor can execute one instruction every 500 nanoseconds as long
-  as memory references are satisfied by its local cache. When a cache miss occurs,
-  the processor is delayed for an additional 2,000 nanoseconds. During half of this
-  additional delay, the bus is dedicated to serving the cache miss. During the other
-  half, the processor cannot continue, but the bus is free to service requests from
-  other processors. On average, each instruction requires 2 memory references. On
-  average, cache misses occur on 1 percent of references. What proportion of the capacity
-  of the bus would a single processor consume, ignoring delays due to competition
-  from other processors?
-
-  (A) 1/50 (B) 1/27 (C) 1/25 (D) 2/27
-
-  A: Let''s think step by step. We know that each instruction requires two memory
-  references per instruction, and that there is an average cache miss rate of one
-  percent.
-
-  Thus a given processor has:
-
-  (1 cache miss / 100 references) * (2 references / instruction) =
-
-  (2 cache misses / 100 instructions), so:
-
-  misses_per_instruction = 1 cache miss / 50 instructions.
-
-  Next, we know that each instruction requires 500 nanoseconds when there is no cache
-  miss, and 500 + 2000 = 2500 nanoseconds when there is a cache miss. Thus:
-
-  50 instructions / (49 * 500) + (1 * 2500) nanoseconds, so:
-
-  instructions_per_ns = 50 instructions / 27000 nanoseconds.
-
-  Now, we know that each cache miss locks the bus for half of the 2000 nanosecond
-  cache miss delay, or 1000 nanoseconds, so:
-
-  lock_ns_per_miss = 1000 nanoseconds / cache miss.
-
-  Thus we can see that on average a single processor will lock the bus for:
-
-  lock_ns_per_miss * misses_per_instruction * instructions_per_ns =
-
-  (1000 nanoseconds / cache miss) * (1 cache miss / 50 instructions) * (50 instructions
-  / 27000 nanoseconds) = 1000 * (1/50) * (50/27000) = 1000/27000 = 1/27. The answer
-  is (B).'
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_college_computer_science
+"dataset_name": "college_computer_science"
+"description": "The following are multiple choice questions (with answers) about college\
+  \ computer science.\n\nQ: Which of the following regular expressions is equivalent\
+  \ to (describes the same set of strings as) (a* + b)*(c + d)?\n(A) a*(c + d)+ b(c\
+  \ + d)\n(B) a*(c + d)* + b(c + d)*\n(C) a*(c + d)+ b*(c + d)\n(D) (a + b)*c +(a\
+  \ + b)*d\nA: Let's think step by step. We know that:\n1. (X* + Y)* = (X + Y)*\n\
+  2. X(Y + Z)? = XY + XZ\nUsing equation 1 we can rewrite (a* + b)*(c + d)? as:\n\
+  3. (a + b)*(c + d)?\nUsing equation 2 we can rewrite equation 3 as:\n(a + b)*c +\
+  \ (a + b)*d The answer is (D).\n\nQ: The Singleton design pattern is used to guarantee\
+  \ that only a single instance of a class may be instantiated. Which of the following\
+  \ is (are) true of this design pattern?\nI. The Singleton class has a static factory\
+  \ method to provide its instance.\nII. The Singleton class can be a subclass of\
+  \ another class.\nIII. The Singleton class has a private constructor.\n(A) I only\n\
+  (B) II only\n(C) III only\n(D) I, II, and III\nA: Let's think step by step. Statement\
+  \ I is a correct statement about a Singleton, because a Singleton restricts instantiation\
+  \ to a single, static method. Statement II is also correct, because there is no\
+  \ inherent restriction regarding the inheritance of a Singleton. Statement III is\
+  \ also correct, because a Singletons must be instantiated only once, so its constructor\
+  \ is made private to prevent any construction except via its static factory method.\n\
+  Given these facts, statements I, II, and III are all correct. The answer is (D).\n\
+  \nQ: A certain pipelined RISC machine has 8 general-purpose registers R0, R1, .\
+  \ . . , R7 and supports the following operations:\nADD Rs1, Rs2, Rd (Add Rs1 to\
+  \ Rs2 and put the sum in Rd)\nMUL Rs1, Rs2, Rd (Multiply Rs1 by Rs2 and put the\
+  \ product in Rd)\nAn operation normally takes one cycle; however, an operation takes\
+  \ two cycles if it produces a result required by the immediately following operation\
+  \ in an operation sequence.\nConsider the expression AB + ABC + BC, where variables\
+  \ A, B, C are located in registers R0, R1, R2. If the contents of these three registers\
+  \ must not be modified, what is the minimum number of clock cycles required for\
+  \ an operation sequence that computes the value of AB + ABC + BC?\n(A) 5 (B) 6 (C)\
+  \ 7 (D) 8\nA: Let's think step by step. First, we are given that A is in R0, B is\
+  \ in R1, and C is in R2.\nNext, we can see that we must compute three multiplies\
+  \ (AB, BC, and ABC) and two adds (AB + ABC, (AB + ABC) + BC) to compute our final\
+  \ answer, resulting in a minimum of five clock cycles.\nNext, we can see that there\
+  \ is no way to avoid at least one pipeline stall when computing our final answer,\
+  \ because to compute our final sum we must wait at least one cycle for the results\
+  \ from the previous stage to be ready. Thus, our minimum number of cycles must be\
+  \ 6.\nWe can verify that we can create a solution that requires only six cycles\
+  \ as follows:\ncompute AB: MUL R0, R1, R3\ncompute BC: MUL R1, R2, R4\ncompute ABC:\
+  \ MUL R3, R4, R5\ncompute AB + BC: ADD R3, R4, R6\nSTALL\ncompute AB + ABC + BC:\
+  \ ADD R5, R6, R7\nSo there are 6 cycles. The answer is (B).\n\nQ: A compiler generates\
+  \ code for the following assignment statement.\nG := (A + B) * C - (D + E) * F\n\
+  The target machine has a single accumulator and a single-address instruction set\
+  \ consisting of instructions load, store, add, subtract, and multiply. For the arithmetic\
+  \ operations, the left operand is taken from the accumulator and the result appears\
+  \ in the accumulator. The smallest possible number of instructions in the resulting\
+  \ code is\n(A) 5 (B) 6 (C) 7 (D) 9\nA: Let's think step by step. We can compute\
+  \ the final answer with the following sequence of operations:\n1. LOAD D  (accumulator\
+  \ = D)\n2. ADD E  (accumulator = D+E)\n3. MUL F  (accumulator = (D+E)*F)\n4. STORE\
+  \ X (X = (D+E)*F)\n5. LOAD A  (accumulator = A)\n6. ADD B  (accumulator = A+B)\n\
+  7. MUL C  (accumulator = (A+B)*C)\n8. SUB X  (accumulator = (A+B)*C - (D+E)*F)\n\
+  9. STORE G (G = (A+B)*C - (D+E)*F)\nThis sequence takes 9 instructions. The answer\
+  \ is (D).\n\nQ: Consider a computer design in which multiple processors, each with\
+  \ a private cache memory, share global memory using a single bus. This bus is the\
+  \ critical system resource. Each processor can execute one instruction every 500\
+  \ nanoseconds as long as memory references are satisfied by its local cache. When\
+  \ a cache miss occurs, the processor is delayed for an additional 2,000 nanoseconds.\
+  \ During half of this additional delay, the bus is dedicated to serving the cache\
+  \ miss. During the other half, the processor cannot continue, but the bus is free\
+  \ to service requests from other processors. On average, each instruction requires\
+  \ 2 memory references. On average, cache misses occur on 1 percent of references.\
+  \ What proportion of the capacity of the bus would a single processor consume, ignoring\
+  \ delays due to competition from other processors?\n(A) 1/50 (B) 1/27 (C) 1/25 (D)\
+  \ 2/27\nA: Let's think step by step. We know that each instruction requires two\
+  \ memory references per instruction, and that there is an average cache miss rate\
+  \ of one percent.\nThus a given processor has:\n(1 cache miss / 100 references)\
+  \ * (2 references / instruction) =\n(2 cache misses / 100 instructions), so:\nmisses_per_instruction\
+  \ = 1 cache miss / 50 instructions.\nNext, we know that each instruction requires\
+  \ 500 nanoseconds when there is no cache miss, and 500 + 2000 = 2500 nanoseconds\
+  \ when there is a cache miss. Thus:\n50 instructions / (49 * 500) + (1 * 2500) nanoseconds,\
+  \ so:\ninstructions_per_ns = 50 instructions / 27000 nanoseconds.\nNow, we know\
+  \ that each cache miss locks the bus for half of the 2000 nanosecond cache miss\
+  \ delay, or 1000 nanoseconds, so:\nlock_ns_per_miss = 1000 nanoseconds / cache miss.\n\
+  Thus we can see that on average a single processor will lock the bus for:\nlock_ns_per_miss\
+  \ * misses_per_instruction * instructions_per_ns =\n(1000 nanoseconds / cache miss)\
+  \ * (1 cache miss / 50 instructions) * (50 instructions / 27000 nanoseconds) = 1000\
+  \ * (1/50) * (50/27000) = 1000/27000 = 1/27. The answer is (B)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_college_computer_science"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_mathematics.yaml

-dataset_name: college_mathematics
-description: "The following are multiple choice questions (with answers) about college\
+"dataset_name": "college_mathematics"
+"description": "The following are multiple choice questions (with answers) about college\
   \ mathematics.\n\nQ: Let V be the set of all real polynomials p(x). Let transformations\
   \ T, S be defined on V by T:p(x) -> xp(x) and S:p(x) -> p'(x) = d/dx p(x), and interpret\
   \ (ST)(p(x)) as S(T(p(x))). Which of the following is true?\n(A) ST = 0 (B) ST =\
   \ T (C) ST = TS (D) ST - TS is the identity map of V onto itself.\nA: Let's think\
-  \ step by step. For a given polynomial $p$ we have\n\\[ST(p) = (xp(x))\u2019 = p(x)\
-  \ + xp\u2019(x)\\]\nand\n\\[TS(p) = xp\u2019(x).\\]\nHence \\[ST(p) - TS(p) = p(x)\
-  \ + xp\u2019(x) - xp\u2019(x).\\] The answer is (D).\n\nQ: Suppose that f(1 + x)\
-  \ = f(x) for all real x. If f is a polynomial and f(5) = 11, then f(15/2)\n(A) -11\
-  \ (B) 0 (C) 11 (D) 33/2\nA: Let's think step by step. The only polynomial so that\
-  \ $f(1 + x) = f(x)$ is a constant polynomial. Hence $f(5) = 11 = f(15/2)$. The answer\
-  \ is (C).\n\nQ: Let A be a real 2x2 matrix. Which of the following statements must\
-  \ be true?\nI. All of the entries of A^2 are nonnegative.\nII. The determinant of\
-  \ A^2 is nonnegative.\nIII. If A has two distinct eigenvalues, then A^2 has two\
-  \ distinct eigenvalues.\n(A) I only (B) II only (C) III only (D) II and III only\n\
-  A: Let's think step by step. We have \\[ det(A^2) = (det(A))^2 \\geq 0,\\] hence\
-  \ II holds.\nIII is false: as a counterexample take a diagonal matrix with -1 and\
-  \ 1 on the diagonal. Then $A^2$ is the identity matrix. The answer is (B).\n\nQ:\
-  \ Let A be the set of all ordered pairs of integers (m, n) such that 7m + 12n =\
-  \ 22. What is the greatest negative number in the set B = {m + n : (m, n) \\in A}?\n\
-  (A) -5 (B) -4 (C) -3 (D) -2\nA: Let's think step by step. We have 12n = 22 - 7m\
-  \ and one of the solutions is $m = -2$, $n = 3$. Then $m + n = 1$, hence we need\
-  \ to look for smaller $m$ in order to make $m + n$ negative. The next solution is\
-  \ $m = -14$ and $n = 10$. For smaller $m$ we have $m + n$ smaller than $-4$. The\
-  \ answer is (B).\n\nQ: A tank initially contains a salt solution of 3 grams of salt\
-  \ dissolved in 100 liters of water. A salt solution containing 0.02 grams of salt\
-  \ per liter of water is sprayed into the tank at a rate of 4 liters per minute.\
-  \ The sprayed solution is continually mixed with the salt solution in the tank,\
-  \ and the mixture flows out of the tank at a rate of 4 liters per minute. If the\
-  \ mixing is instantaneous, how many grams of salt are in the tank after 100 minutes\
-  \ have elapsed?\n(A) 2 (B) 2 - e^-2 (C) 2 + e^-2 (D) 2 + e^-4\nA: Let's think step\
-  \ by step. For all $t \\in \\mathbb{R}$, let $s(t)$ denote the number grams of salt\
-  \ in the tank at the $t$ minute mark. Then $s(0) = 3$.\nWe use $s$ and $s(t)$ interchangeably.\
-  \ We also use $s^{\\prime}$ and $s^{\\prime}(t)$ interchangeably. The solution sprayed\
-  \ into the tank adds $(0.02) 4=2 / 25$ grams of salt per minute. There are always\
-  \ 100 liters of liquid in the tank, containing $s$ grams of salt. So the density\
-  \ of salt in the tank is $s / 100$ grams per liter. The flow of water out of the\
-  \ tank therefore subtracts $4(s / 100)=s / 25$ grams of salt per minute. Then, for\
-  \ all $t \\in \\mathbb{R}$, we have $s^{\\prime}(t)=(2 / 25)-(s / 25)=(2-s) / 25$,\
-  \ and so $[s(t)=2] \\Rightarrow\\left[s^{\\prime}(t)=0\right]$. For all $t \\in\
-  \ \\mathbb{R}$,\n$$\n\frac{d}{d t}[\\ln (s-2)]=\frac{s^{\\prime}}{s-2}=\frac{-1}{25}=\f\
-  rac{d}{d t}\\left[-\frac{t}{25}\right] .\n$$\nChoose $C \\in \\mathbb{R}$ such that,\
-  \ for all $t \\in \\mathbb{R}, \\ln ((s(t)-2))=-[t / 25]+C$. Let $K:=e^{C}$. Then,\
-  \ for all $t \\in \\mathbb{R}$, we have $(s(t))-2=K e^{-t / 25}$, and so $s(t)=2+K\
-  \ e^{-t / 25}$. Then $3=s(0)=2+K e^{0}=2+K$, so $K=1$. Then $s(100)=2+K e^{-100\
-  \ / 25}=2+1 \\cdot e^{-4}=2+e^{-4}$. The answer is (D)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_college_mathematics
+  \ step by step. For a given polynomial $p$ we have\n\\[ST(p) = (xp(x))’ = p(x) +\
+  \ xp’(x)\\]\nand\n\\[TS(p) = xp’(x).\\]\nHence \\[ST(p) - TS(p) = p(x) + xp’(x)\
+  \ - xp’(x).\\] The answer is (D).\n\nQ: Suppose that f(1 + x) = f(x) for all real\
+  \ x. If f is a polynomial and f(5) = 11, then f(15/2)\n(A) -11 (B) 0 (C) 11 (D)\
+  \ 33/2\nA: Let's think step by step. The only polynomial so that $f(1 + x) = f(x)$\
+  \ is a constant polynomial. Hence $f(5) = 11 = f(15/2)$. The answer is (C).\n\n\
+  Q: Let A be a real 2x2 matrix. Which of the following statements must be true?\n\
+  I. All of the entries of A^2 are nonnegative.\nII. The determinant of A^2 is nonnegative.\n\
+  III. If A has two distinct eigenvalues, then A^2 has two distinct eigenvalues.\n\
+  (A) I only (B) II only (C) III only (D) II and III only\nA: Let's think step by\
+  \ step. We have \\[ det(A^2) = (det(A))^2 \\geq 0,\\] hence II holds.\nIII is false:\
+  \ as a counterexample take a diagonal matrix with -1 and 1 on the diagonal. Then\
+  \ $A^2$ is the identity matrix. The answer is (B).\n\nQ: Let A be the set of all\
+  \ ordered pairs of integers (m, n) such that 7m + 12n = 22. What is the greatest\
+  \ negative number in the set B = {m + n : (m, n) \\in A}?\n(A) -5 (B) -4 (C) -3\
+  \ (D) -2\nA: Let's think step by step. We have 12n = 22 - 7m and one of the solutions\
+  \ is $m = -2$, $n = 3$. Then $m + n = 1$, hence we need to look for smaller $m$\
+  \ in order to make $m + n$ negative. The next solution is $m = -14$ and $n = 10$.\
+  \ For smaller $m$ we have $m + n$ smaller than $-4$. The answer is (B).\n\nQ: A\
+  \ tank initially contains a salt solution of 3 grams of salt dissolved in 100 liters\
+  \ of water. A salt solution containing 0.02 grams of salt per liter of water is\
+  \ sprayed into the tank at a rate of 4 liters per minute. The sprayed solution is\
+  \ continually mixed with the salt solution in the tank, and the mixture flows out\
+  \ of the tank at a rate of 4 liters per minute. If the mixing is instantaneous,\
+  \ how many grams of salt are in the tank after 100 minutes have elapsed?\n(A) 2\
+  \ (B) 2 - e^-2 (C) 2 + e^-2 (D) 2 + e^-4\nA: Let's think step by step. For all $t\
+  \ \\in \\mathbb{R}$, let $s(t)$ denote the number grams of salt in the tank at the\
+  \ $t$ minute mark. Then $s(0) = 3$.\nWe use $s$ and $s(t)$ interchangeably. We also\
+  \ use $s^{\\prime}$ and $s^{\\prime}(t)$ interchangeably. The solution sprayed into\
+  \ the tank adds $(0.02) 4=2 / 25$ grams of salt per minute. There are always 100\
+  \ liters of liquid in the tank, containing $s$ grams of salt. So the density of\
+  \ salt in the tank is $s / 100$ grams per liter. The flow of water out of the tank\
+  \ therefore subtracts $4(s / 100)=s / 25$ grams of salt per minute. Then, for all\
+  \ $t \\in \\mathbb{R}$, we have $s^{\\prime}(t)=(2 / 25)-(s / 25)=(2-s) / 25$, and\
+  \ so $[s(t)=2] \\Rightarrow\\left[s^{\\prime}(t)=0\right]$. For all $t \\in \\mathbb{R}$,\n\
+  $$\n\frac{d}{d t}[\\ln (s-2)]=\frac{s^{\\prime}}{s-2}=\frac{-1}{25}=\frac{d}{d t}\\\
+  left[-\frac{t}{25}\right] .\n$$\nChoose $C \\in \\mathbb{R}$ such that, for all\
+  \ $t \\in \\mathbb{R}, \\ln ((s(t)-2))=-[t / 25]+C$. Let $K:=e^{C}$. Then, for all\
+  \ $t \\in \\mathbb{R}$, we have $(s(t))-2=K e^{-t / 25}$, and so $s(t)=2+K e^{-t\
+  \ / 25}$. Then $3=s(0)=2+K e^{0}=2+K$, so $K=1$. Then $s(100)=2+K e^{-100 / 25}=2+1\
+  \ \\cdot e^{-4}=2+e^{-4}$. The answer is (D)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_college_mathematics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_medicine.yaml

-dataset_name: college_medicine
-description: "The following are multiple choice questions (with answers) about college\
+"dataset_name": "college_medicine"
+"description": "The following are multiple choice questions (with answers) about college\
   \ medicine.\n\nQ: An expected side effect of creatine supplementation is:\n(A) muscle\
   \ weakness. (B) gain in body mass. (C) muscle cramps. (D) loss of electrolytes.\n\
   A: Let's think step by step. We refer to Wikipedia articles on medicine for help.\
@@ -9,44 +9,44 @@ description: "The following are multiple choice questions (with answers) about c
   \ endurance runners have a high proportion of Type I fibres in their leg muscles\
   \ (C) Liver glycogen is important in the maintenance of the blood glucose concentration\
   \ (D) Insulin promotes glucose uptake by all tissues in the body\nA: Let's think\
-  \ step by step. We refer to Wikipedia articles on medicine for help. Let\u2019s\
-  \ solve this step by step and go over each choice: \n(A) \u201CMuscle glycogen is\
-  \ broken down enzymatically to glucose-1-phosphate\u201D: This is a correct statement.\n\
-  (B) \u201CElite endurance runners have a high proportion of Type I fibres in their\
-  \ leg muscles\u201D: This is a correct statement.\n(C) \u201CLiver glycogen is important\
-  \ in the maintenance of the blood glucose concentration\u201D: This is a correct\
-  \ statement. \n(D) \u201CInsulin promotes glucose uptake by all tissues in the body\u201D\
-  : This is not a correct statement, because insulin promotes glucose uptake by the\
-  \ liver, adipose tissue, and muscle, but not all tissues. For instance, the tissues\
-  \ in the brain and red blood cells are not affected by insulin. The answer is (D).\n\
-  \nQ: A high school science teacher fills a 1 liter bottle with pure nitrogen and\
-  \ seals the lid. The pressure is 1.70 atm, and the room temperature is 25\xB0C.\
-  \ Which two variables will both increase the pressure of the system, if all other\
-  \ variables are held constant?\n(A) Increasing temperature, increasing moles of\
-  \ gas (B) Increasing temperature, increasing volume (C) Decreasing volume, decreasing\
-  \ temperature (D) Decreasing moles of gas, increasing volume\nA: Let's think step\
-  \ by step. We refer to Wikipedia articles on medicine for help. The relevant equation\
-  \ for this is the ideal gas law: PV=nRT. To increase the pressure of the system\
-  \ (P), then either n (number of moles of the gas) or T (temperature) have to increase.\
-  \ The answer is (A).\n\nQ: In a genetic test of a newborn, a rare genetic disorder\
-  \ is found that has X-linked recessive transmission. Which of the following statements\
-  \ is likely true regarding the pedigree of this disorder?\n(A) All descendants on\
-  \ the maternal side will have the disorder. (B) Females will be approximately twice\
-  \ as affected as males in this family. (C) All daughters of an affected male will\
-  \ be affected. (D) There will be equal distribution of males and females affected.\n\
-  A: Let's think step by step. We refer to Wikipedia articles on medicine for help.\
-  \ Let\u2019s solve this step by step. Let's recall first that females have two X\
-  \ chromosomes, while males have one X and one Y chromosome. This is an important\
-  \ fact we need to know before answering this question. \nBecause a male can only\
-  \ pass his only one X chromosome to a daughter, if he is affected by this rare genetic\
-  \ disorder, then we know for sure that he will pass this rare genetic disorder to\
-  \ all his future-born daughters. Therefore, \u201C(C): All daughters of an affected\
-  \ male will be affected\u201D is a correct statement. The answer is (C).\n\nQ: Glucose\
-  \ is transported into the muscle cell:\n(A) via protein transporters called GLUT4.\
-  \ (B) only in the presence of insulin. (C) via hexokinase. (D) via monocarbylic\
-  \ acid transporters.\nA: Let's think step by step. We refer to Wikipedia articles\
-  \ on medicine for help. Glucose (also known as the blood sugar) is the main sugar\
-  \ found in the human body. It is transported into the muscle cell via diffusion\
-  \ through protein transporters called GLUT4. The answer is (A)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_college_medicine
+  \ step by step. We refer to Wikipedia articles on medicine for help. Let’s solve\
+  \ this step by step and go over each choice: \n(A) “Muscle glycogen is broken down\
+  \ enzymatically to glucose-1-phosphate”: This is a correct statement.\n(B) “Elite\
+  \ endurance runners have a high proportion of Type I fibres in their leg muscles”:\
+  \ This is a correct statement.\n(C) “Liver glycogen is important in the maintenance\
+  \ of the blood glucose concentration”: This is a correct statement. \n(D) “Insulin\
+  \ promotes glucose uptake by all tissues in the body”: This is not a correct statement,\
+  \ because insulin promotes glucose uptake by the liver, adipose tissue, and muscle,\
+  \ but not all tissues. For instance, the tissues in the brain and red blood cells\
+  \ are not affected by insulin. The answer is (D).\n\nQ: A high school science teacher\
+  \ fills a 1 liter bottle with pure nitrogen and seals the lid. The pressure is 1.70\
+  \ atm, and the room temperature is 25°C. Which two variables will both increase\
+  \ the pressure of the system, if all other variables are held constant?\n(A) Increasing\
+  \ temperature, increasing moles of gas (B) Increasing temperature, increasing volume\
+  \ (C) Decreasing volume, decreasing temperature (D) Decreasing moles of gas, increasing\
+  \ volume\nA: Let's think step by step. We refer to Wikipedia articles on medicine\
+  \ for help. The relevant equation for this is the ideal gas law: PV=nRT. To increase\
+  \ the pressure of the system (P), then either n (number of moles of the gas) or\
+  \ T (temperature) have to increase. The answer is (A).\n\nQ: In a genetic test of\
+  \ a newborn, a rare genetic disorder is found that has X-linked recessive transmission.\
+  \ Which of the following statements is likely true regarding the pedigree of this\
+  \ disorder?\n(A) All descendants on the maternal side will have the disorder. (B)\
+  \ Females will be approximately twice as affected as males in this family. (C) All\
+  \ daughters of an affected male will be affected. (D) There will be equal distribution\
+  \ of males and females affected.\nA: Let's think step by step. We refer to Wikipedia\
+  \ articles on medicine for help. Let’s solve this step by step. Let's recall first\
+  \ that females have two X chromosomes, while males have one X and one Y chromosome.\
+  \ This is an important fact we need to know before answering this question. \nBecause\
+  \ a male can only pass his only one X chromosome to a daughter, if he is affected\
+  \ by this rare genetic disorder, then we know for sure that he will pass this rare\
+  \ genetic disorder to all his future-born daughters. Therefore, “(C): All daughters\
+  \ of an affected male will be affected” is a correct statement. The answer is (C).\n\
+  \nQ: Glucose is transported into the muscle cell:\n(A) via protein transporters\
+  \ called GLUT4. (B) only in the presence of insulin. (C) via hexokinase. (D) via\
+  \ monocarbylic acid transporters.\nA: Let's think step by step. We refer to Wikipedia\
+  \ articles on medicine for help. Glucose (also known as the blood sugar) is the\
+  \ main sugar found in the human body. It is transported into the muscle cell via\
+  \ diffusion through protein transporters called GLUT4. The answer is (A)."
+"group": "mmlu_flan_cot_fewshot_other"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_college_medicine"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_college_physics.yaml

-dataset_name: college_physics
-description: 'The following are multiple choice questions (with answers) about college
-  physics.
-
-
-  Q: A refracting telescope consists of two converging lenses separated by 100 cm.
-  The eye-piece lens has a focal length of 20 cm. The angular magnification of the
-  telescope is
-
-  (A) 4 (B) 5 (C) 6 (D) 20
-
-  A: Let''s think step by step. In a refracting telescope, if both lenses are converging,
-  the focus of both lenses must be between the two lenses, and thus the focal lengths
-  of the two lenses must add up to their separation. Since the focal length of one
-  lens is 20 cm, the focal length of the other must be 80 cm. The magnification is
-  the ratio of these two focal lengths, or 4. The answer is (A).
-
-
-  Q: The muon decays with a characteristic lifetime of about 10^-6 second into an
-  electron, a muon neutrino, and an electron antineutrino. The muon is forbidden from
-  decaying into an electron and just a single neutrino by the law of conservation
-  of
-
-  (A) charge (B) mass (C) energy and momentum (D) lepton number
-
-  A: Let''s think step by step. Lepton number must be conserved, meaning the total
-  number of leptons minus the number of antileptons. If a muon decays into an electron
-  and a single neutrino, the total lepton number would go from one to two, violating
-  lepton number conservation. The answer is (D).
-
-
-  Q: One end of a Nichrome wire of length 2L and cross-sectional area A is attached
-  to an end of another Nichrome wire of length L and cross- sectional area 2A. If
-  the free end of the longer wire is at an electric potential of 8.0 volts, and the
-  free end of the shorter wire is at an electric potential of 1.0 volt, the potential
-  at the junction of the two wires is most nearly equal to
-
-  (A) 2.4 V (B) 3.3 V (C) 4.5 V (D) 5.7 V
-
-  A: Let''s think step by step. This is a simple voltage divider problem, where the
-  longer wire has a resistance four times that of the shorter end. So the voltage
-  divider ratio is 1 / 5, meaning that the potential in the middle is 1.0 V + (8.0
-  V - 1.0 V) * 1/5 = 2.4 V. The answer is (A).
-
-
-  Q: A refracting telescope consists of two converging lenses separated by 100 cm.
-  The eye-piece lens has a focal length of 20 cm. The angular magnification of the
-  telescope is
-
-  (A) 4 (B) 5 (C) 6 (D) 20
-
-  A: Let''s think step by step. In a refracting telescope, if both lenses are converging,
-  the focus of both lenses must be between the two lenses, and thus the focal lengths
-  of the two lenses must add up to their separation. Since the focal length of one
-  lens is 20 cm, the focal length of the other must be 80 cm. The magnification is
-  the ratio of these two focal lengths, or 4. The answer is (A).
-
-
-  Q: For which of the following thermodynamic processes is the increase in the internal
-  energy of an ideal gas equal to the heat added to the gas?
-
-  (A) Constant temperature (B) Constant volume (C) Constant pressure (D) Adiabatic
-
-  A: Let''s think step by step. Heat added to the gas can go into the gases internal
-  energy or work done against an external force. However, if the volume of the gas
-  container is constant, no work will be done (since work is pressure times change
-  in volume). So, at constant volume, all of the heat goes into the internal energy.
-  The answer is (B).'
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_college_physics
+"dataset_name": "college_physics"
+"description": "The following are multiple choice questions (with answers) about college\
+  \ physics.\n\nQ: A refracting telescope consists of two converging lenses separated\
+  \ by 100 cm. The eye-piece lens has a focal length of 20 cm. The angular magnification\
+  \ of the telescope is\n(A) 4 (B) 5 (C) 6 (D) 20\nA: Let's think step by step. In\
+  \ a refracting telescope, if both lenses are converging, the focus of both lenses\
+  \ must be between the two lenses, and thus the focal lengths of the two lenses must\
+  \ add up to their separation. Since the focal length of one lens is 20 cm, the focal\
+  \ length of the other must be 80 cm. The magnification is the ratio of these two\
+  \ focal lengths, or 4. The answer is (A).\n\nQ: The muon decays with a characteristic\
+  \ lifetime of about 10^-6 second into an electron, a muon neutrino, and an electron\
+  \ antineutrino. The muon is forbidden from decaying into an electron and just a\
+  \ single neutrino by the law of conservation of\n(A) charge (B) mass (C) energy\
+  \ and momentum (D) lepton number\nA: Let's think step by step. Lepton number must\
+  \ be conserved, meaning the total number of leptons minus the number of antileptons.\
+  \ If a muon decays into an electron and a single neutrino, the total lepton number\
+  \ would go from one to two, violating lepton number conservation. The answer is\
+  \ (D).\n\nQ: One end of a Nichrome wire of length 2L and cross-sectional area A\
+  \ is attached to an end of another Nichrome wire of length L and cross- sectional\
+  \ area 2A. If the free end of the longer wire is at an electric potential of 8.0\
+  \ volts, and the free end of the shorter wire is at an electric potential of 1.0\
+  \ volt, the potential at the junction of the two wires is most nearly equal to\n\
+  (A) 2.4 V (B) 3.3 V (C) 4.5 V (D) 5.7 V\nA: Let's think step by step. This is a\
+  \ simple voltage divider problem, where the longer wire has a resistance four times\
+  \ that of the shorter end. So the voltage divider ratio is 1 / 5, meaning that the\
+  \ potential in the middle is 1.0 V + (8.0 V - 1.0 V) * 1/5 = 2.4 V. The answer is\
+  \ (A).\n\nQ: A refracting telescope consists of two converging lenses separated\
+  \ by 100 cm. The eye-piece lens has a focal length of 20 cm. The angular magnification\
+  \ of the telescope is\n(A) 4 (B) 5 (C) 6 (D) 20\nA: Let's think step by step. In\
+  \ a refracting telescope, if both lenses are converging, the focus of both lenses\
+  \ must be between the two lenses, and thus the focal lengths of the two lenses must\
+  \ add up to their separation. Since the focal length of one lens is 20 cm, the focal\
+  \ length of the other must be 80 cm. The magnification is the ratio of these two\
+  \ focal lengths, or 4. The answer is (A).\n\nQ: For which of the following thermodynamic\
+  \ processes is the increase in the internal energy of an ideal gas equal to the\
+  \ heat added to the gas?\n(A) Constant temperature (B) Constant volume (C) Constant\
+  \ pressure (D) Adiabatic\nA: Let's think step by step. Heat added to the gas can\
+  \ go into the gases internal energy or work done against an external force. However,\
+  \ if the volume of the gas container is constant, no work will be done (since work\
+  \ is pressure times change in volume). So, at constant volume, all of the heat goes\
+  \ into the internal energy. The answer is (B)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_college_physics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_computer_security.yaml

-dataset_name: computer_security
-description: "The following are multiple choice questions (with answers) about computer\
+"dataset_name": "computer_security"
+"description": "The following are multiple choice questions (with answers) about computer\
   \ security.\n\nQ: SHA-1 has a message digest of\n(A) 160 bits (B) 512 bits (C) 628\
   \ bits (D) 820 bits\nA: Let's think step by step. Since SHA-1 is a hash function\
   \ which takes an input and produces a 160-bit (20-byte) hash value, its message\
   \ digest is 160 bits. The answer is (A).\n\nQ: _____________ can modify data on\
-  \ your system \u2013 so that your system doesn\u2019t run correctly or you can no\
-  \ longer access specific data, or it may even ask for ransom in order to give your\
-  \ access.\n(A) IM \u2013 Trojans (B) Backdoor Trojans (C) Trojan-Downloader (D)\
-  \ Ransom Trojan\nA: Let's think step by step. The system is asking for trojans,\
-  \ which are for ransom, which means ransom trojan. The answer is (D).\n\nQ: What\
-  \ is ethical hacking?\n(A) \"Hacking\" ethics so they justify unintended selfish\
-  \ behavior (B) Hacking systems (e.g., during penetration testing) to expose vulnerabilities\
-  \ so they can be fixed, rather than exploited (C) Hacking into systems run by those\
-  \ whose ethics you disagree with (D) A slang term for rapid software development,\
-  \ e.g., as part of hackathons\nA: Let's think step by step. Ethical hacking is a\
-  \ process of detecting vulnerabilities in an application, system, or organization's\
-  \ infrastructure that an attacker can use to exploit an individual or organization.\
-  \ They use this process to prevent cyberattacks and security breaches by lawfully\
-  \ hacking into the systems and looking for weak points. The answer is (B).\n\nQ:\
-  \ The ____________ is anything which your search engine cannot search.\n(A) Haunted\
-  \ web (B) World Wide Web (C) Surface web (D) Deep Web\nA: Let's think step by step.\
-  \ The search engine searches on the Surface Web, which is the portion of the world\
-  \ wide web which is visible so (B,C) are wrong. The Haunted Web doesn\u2019t correspond\
-  \ to an internet concept. The Deep Web is the part of the World Wide Web which is\
-  \ not indexed. The answer is (D).\n\nQ: Exploitation of the Heartbleed bug permits\n\
-  (A) overwriting cryptographic keys in memory (B) a kind of code injection (C) a\
-  \ read outside bounds of a buffer (D) a format string attack\nA: Let's think step\
-  \ by step. The Heartbleed Bug is a serious vulnerability in the popular OpenSSL\
-  \ cryptographic software library. Heartbleed resulted from improper input validation\
-  \ (due to a missing bounds check) in the implementation of the TLS heartbeat extension.\
-  \ The vulnerability was classified as a buffer over-read, a situation where more\
-  \ data can be read than should be allowed. The answer is (C)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_computer_security
+  \ your system – so that your system doesn’t run correctly or you can no longer access\
+  \ specific data, or it may even ask for ransom in order to give your access.\n(A)\
+  \ IM – Trojans (B) Backdoor Trojans (C) Trojan-Downloader (D) Ransom Trojan\nA:\
+  \ Let's think step by step. The system is asking for trojans, which are for ransom,\
+  \ which means ransom trojan. The answer is (D).\n\nQ: What is ethical hacking?\n\
+  (A) \"Hacking\" ethics so they justify unintended selfish behavior (B) Hacking systems\
+  \ (e.g., during penetration testing) to expose vulnerabilities so they can be fixed,\
+  \ rather than exploited (C) Hacking into systems run by those whose ethics you disagree\
+  \ with (D) A slang term for rapid software development, e.g., as part of hackathons\n\
+  A: Let's think step by step. Ethical hacking is a process of detecting vulnerabilities\
+  \ in an application, system, or organization's infrastructure that an attacker can\
+  \ use to exploit an individual or organization. They use this process to prevent\
+  \ cyberattacks and security breaches by lawfully hacking into the systems and looking\
+  \ for weak points. The answer is (B).\n\nQ: The ____________ is anything which your\
+  \ search engine cannot search.\n(A) Haunted web (B) World Wide Web (C) Surface web\
+  \ (D) Deep Web\nA: Let's think step by step. The search engine searches on the Surface\
+  \ Web, which is the portion of the world wide web which is visible so (B,C) are\
+  \ wrong. The Haunted Web doesn’t correspond to an internet concept. The Deep Web\
+  \ is the part of the World Wide Web which is not indexed. The answer is (D).\n\n\
+  Q: Exploitation of the Heartbleed bug permits\n(A) overwriting cryptographic keys\
+  \ in memory (B) a kind of code injection (C) a read outside bounds of a buffer (D)\
+  \ a format string attack\nA: Let's think step by step. The Heartbleed Bug is a serious\
+  \ vulnerability in the popular OpenSSL cryptographic software library. Heartbleed\
+  \ resulted from improper input validation (due to a missing bounds check) in the\
+  \ implementation of the TLS heartbeat extension. The vulnerability was classified\
+  \ as a buffer over-read, a situation where more data can be read than should be\
+  \ allowed. The answer is (C)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_computer_security"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_conceptual_physics.yaml

-dataset_name: conceptual_physics
-description: "\nThe following are multiple choice questions (with answers) about conceptual\
-  \ physics.\n\nQ: Colors in a soap bubble result from light\n(A) converted to a different\
-  \ frequency (B) deflection (C) interference (D) polarization\nA: Let's think step\
-  \ by step. In a soap bubble film, the light bounces between the two soap-air interfaces\
-  \ many times, interfering with itself constructively or destructively depending\
-  \ on the width of the film. This results in different colors being visible. The\
-  \ answer is (C).\n\nQ: Compared with the mass of a uranium atom undergoing fission,\
-  \ the combined masses of the products after fission are\n(A) less (B) more (C) the\
-  \ same (D) zero\nA: Let's think step by step. Fission releases energy, which comes\
-  \ from the rest mass of its initial nucleus. Thus the mass of the products is less\
-  \ than the mass of the reactant uranium nucleus. The answer is (A).\n\nQ: Things\
-  \ that are equivalent according to the equivalence principle are\n(A) space and\
-  \ time. (B) a traveling twin and a stay-at-home twin. (C) gravity and acceleration.\
-  \ (D) mass and energy.\nA: Let's think step by step. Einstein\u2019s famous equivalence\
-  \ principle states that gravity and acceleration are equivalent. The answer is (C).\n\
-  \nQ: Which of these three elements has the most mass per nucleon?\n(A) Hydrogen\
-  \ (B) Iron (C) Uranium (D) Same in each\nA: Let's think step by step. Due to nuclear\
-  \ binding energy, the mass of an atomic nucleus is less than the sum of individual\
-  \ masses of the free constituent protons and neutrons; this is known as the mass\
-  \ defect. Hydrogen has no mass defect because it has only a single nucleon, so it\
-  \ will have the most mass per nucleon. The answer is (A).\n\nQ: A model airplane\
-  \ flies slower when flying into the wind and faster with wind at its back. When\
-  \ launched at right angles to the wind a cross wind its groundspeed compared with\
-  \ flying in still air is\n(A) the same (B) greater (C) less (D) either greater or\
-  \ less depending on wind speed\nA: Let's think step by step. The plane\u2019s speed\
-  \ in the direction of the wind is greater than it would be in the absence of wind,\
-  \ and its direction orthogonal to the wind is the same as it would be in the absence\
-  \ of the wind. The total speed, which is these two components added in quadrature,\
-  \ is thus greater than the speed in still air. The answer is (B)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_conceptual_physics
+"dataset_name": "conceptual_physics"
+"description": "\nThe following are multiple choice questions (with answers) about\
+  \ conceptual physics.\n\nQ: Colors in a soap bubble result from light\n(A) converted\
+  \ to a different frequency (B) deflection (C) interference (D) polarization\nA:\
+  \ Let's think step by step. In a soap bubble film, the light bounces between the\
+  \ two soap-air interfaces many times, interfering with itself constructively or\
+  \ destructively depending on the width of the film. This results in different colors\
+  \ being visible. The answer is (C).\n\nQ: Compared with the mass of a uranium atom\
+  \ undergoing fission, the combined masses of the products after fission are\n(A)\
+  \ less (B) more (C) the same (D) zero\nA: Let's think step by step. Fission releases\
+  \ energy, which comes from the rest mass of its initial nucleus. Thus the mass of\
+  \ the products is less than the mass of the reactant uranium nucleus. The answer\
+  \ is (A).\n\nQ: Things that are equivalent according to the equivalence principle\
+  \ are\n(A) space and time. (B) a traveling twin and a stay-at-home twin. (C) gravity\
+  \ and acceleration. (D) mass and energy.\nA: Let's think step by step. Einstein’s\
+  \ famous equivalence principle states that gravity and acceleration are equivalent.\
+  \ The answer is (C).\n\nQ: Which of these three elements has the most mass per nucleon?\n\
+  (A) Hydrogen (B) Iron (C) Uranium (D) Same in each\nA: Let's think step by step.\
+  \ Due to nuclear binding energy, the mass of an atomic nucleus is less than the\
+  \ sum of individual masses of the free constituent protons and neutrons; this is\
+  \ known as the mass defect. Hydrogen has no mass defect because it has only a single\
+  \ nucleon, so it will have the most mass per nucleon. The answer is (A).\n\nQ: A\
+  \ model airplane flies slower when flying into the wind and faster with wind at\
+  \ its back. When launched at right angles to the wind a cross wind its groundspeed\
+  \ compared with flying in still air is\n(A) the same (B) greater (C) less (D) either\
+  \ greater or less depending on wind speed\nA: Let's think step by step. The plane’s\
+  \ speed in the direction of the wind is greater than it would be in the absence\
+  \ of wind, and its direction orthogonal to the wind is the same as it would be in\
+  \ the absence of the wind. The total speed, which is these two components added\
+  \ in quadrature, is thus greater than the speed in still air. The answer is (B)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_conceptual_physics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_econometrics.yaml

-dataset_name: econometrics
-description: "The following are multiple choice questions (with answers) about econometrics.\n\
+"dataset_name": "econometrics"
+"description": "The following are multiple choice questions (with answers) about econometrics.\n\
   \nQ: Suppose now that a researcher wishes to use information criteria to determine\
   \ the optimal lag length for a VAR. 500 observations are available for the bi-variate\
   \ VAR, and the values of the determinant of the variance-covariance matrix of residuals\
   \ are 0.0336, 0.0169, 0.0084, and 0.0062 for 1, 2, 3, and 4 lags respectively. What\
   \ is the optimal model order according to Akaike's information criterion?\n(A) 1\
   \ lag (B) 2 lags (C) 3 lags (D) 4 lags\nA: Let's think step by step. We refer to\
-  \ Wikipedia articles on econometrics for help. Let\u2019s solve this problem step\
-  \ by step. First of all, let\u2019s recall that for a given set of data, Akaike's\
-  \ information criterion (AIC) allows us to measure how well a statistical model\
-  \ fits the data; it is an estimator of prediction error. Here in this problem we\
-  \ will need to use the formula ln(det(sigma_hat)) + (2 * k / T) to determine the\
-  \ values of Akaike\u2019s criterion, where ln denotes the natural log function,\
-  \ det the determinant function, k the total number of parameters in total (across\
-  \ both equations), and T the number of observations (which, in this case, is equal\
-  \ to 500). For 1 lag, the number of parameters in total is equal to 6; for 2 lags,\
-  \ it is 10; for 3 lags, it is 14; and for 4 lags, it is 18. Now, let\u2019s calculate\
-  \ the values of the criterion for each lag:\n(A) 1 lag: ln(0.0336) + (2 * 6 / 500)\
-  \ = ln(0.0336) + (12 / 500) = -3.369\n(B) 2 lags: ln(0.0169) + (2 * 10 / 500) =\
-  \ ln(0.0169) + (20 / 500) = -4.040\n(C) 3 lags: ln(0.0084) + (2 * 14 / 500) = ln(0.0084)\
-  \ + (28 / 500) =-4.724\n(D) 4 lags: ln(0.0062) + (2 * 18 / 500) = ln(0.0062) + (36\
-  \ / 500) =-5.011\nBecause the optimal model order according to AIC minimizes the\
-  \ information criterion, the answer should be the one with the lowest value. In\
-  \ this case, (D) has the lowest value. The answer is (C).\n\nQ: Consider the following\
-  \ AR(1) model with the disturbances having zero mean and unit variance\nyt = 0.2\
-  \ + 0.4 yt-1 + ut\nThe (unconditional) mean of y will be given by\n(A) 0.2 (B) 0.4\
-  \ (C) 0.5 (D) 0.33\nA: Let's think step by step. We refer to Wikipedia articles\
-  \ on econometrics for help. Let\u2019s solve this problem step by step. If we have\
-  \ a an AR(1) model with the disturbances having zero mean and unit variance, then\
-  \ the unconditional mean of y is equal to the following:\nunconditional mean of\
-  \ y = (the intercept term) / (1 - autoregressive coefficient)\nWe know that the\
-  \ intercept term is 0.2 and the autoregressive coefficient is 0.4; thus, we have:\n\
-  unconditional mean of y = (0.2) / (1 - 0.4) = (0.2) / (0.6) = 2 / 6 = 1 / 3, which\
-  \ is approximately 0.33. That means that the answer should be (D) 0.33. The answer\
-  \ is (D).\n\nQ: What would be then consequences for the OLS estimator if heteroscedasticity\
-  \ is present in a regression model but ignored?\n(A) It will be biased (B) It will\
-  \ be inconsistent (C) It will be inefficient (D) All of (a), (b) and (c) will be\
-  \ true.\nA: Let's think step by step. We refer to Wikipedia articles on econometrics\
-  \ for help. Heteroscedasticity refers to the condition where the variance of the\
-  \ error terms is not constant across multiple observations. If heteroscedasticity\
-  \ is present in a regression model, then the coefficient estimates in the OLS estimator\
-  \ will be not only unbiased and consistent but also inefficient. Because (A) and\
-  \ (B) are incorrect choices and (C) is a correct choice, (D) cannot be the right\
-  \ answer. Ultimately, (C) is the only true choice. The answer is (C).\n\nQ: Suppose\
-  \ that a test statistic has associated with it a p-value of 0.08. Which one of the\
-  \ following statements is true?\n(i) If the size of the test were exactly 8%, we\
-  \ would be indifferent between rejecting and not rejecting the null hypothesis\n\
-  (ii) The null would be rejected if a 10% size of test were used\n(iii) The null\
-  \ would not be rejected if a 1% size of test were used\n(iv) The null would be rejected\
-  \ if a 5% size of test were used.\n(A) (ii) and (iv) only (B) (i) and (iii) only\
-  \ (C) (i), (ii), and (iii) only (D) (i), (ii), (iii), and (iv).\nA: Let's think\
-  \ step by step. We refer to Wikipedia articles on econometrics for help. Let\u2019\
-  s reason about each of the options.\n(i) is a true statement.\n(ii) is a true statement.\n\
-  (iii) is a true statement.\n(iv) is not a true statement. Thus, (i), (ii), and (iii)\
-  \ are true. The answer is (C).\n\nQ: For a stationary autoregressive process, shocks\
-  \ will\n(A) Eventually die away (B) Persist indefinitely (C) Grow exponentially\
-  \ (D) Never occur\nA: Let's think step by step. We refer to Wikipedia articles on\
-  \ econometrics for help. This is a formal logic problem about stationally process.\
-  \ For a stationary autoregressive process, shocks will eventually die away. The\
-  \ answer is (A)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_econometrics
+  \ Wikipedia articles on econometrics for help. Let’s solve this problem step by\
+  \ step. First of all, let’s recall that for a given set of data, Akaike's information\
+  \ criterion (AIC) allows us to measure how well a statistical model fits the data;\
+  \ it is an estimator of prediction error. Here in this problem we will need to use\
+  \ the formula ln(det(sigma_hat)) + (2 * k / T) to determine the values of Akaike’s\
+  \ criterion, where ln denotes the natural log function, det the determinant function,\
+  \ k the total number of parameters in total (across both equations), and T the number\
+  \ of observations (which, in this case, is equal to 500). For 1 lag, the number\
+  \ of parameters in total is equal to 6; for 2 lags, it is 10; for 3 lags, it is\
+  \ 14; and for 4 lags, it is 18. Now, let’s calculate the values of the criterion\
+  \ for each lag:\n(A) 1 lag: ln(0.0336) + (2 * 6 / 500) = ln(0.0336) + (12 / 500)\
+  \ = -3.369\n(B) 2 lags: ln(0.0169) + (2 * 10 / 500) = ln(0.0169) + (20 / 500) =\
+  \ -4.040\n(C) 3 lags: ln(0.0084) + (2 * 14 / 500) = ln(0.0084) + (28 / 500) =-4.724\n\
+  (D) 4 lags: ln(0.0062) + (2 * 18 / 500) = ln(0.0062) + (36 / 500) =-5.011\nBecause\
+  \ the optimal model order according to AIC minimizes the information criterion,\
+  \ the answer should be the one with the lowest value. In this case, (D) has the\
+  \ lowest value. The answer is (C).\n\nQ: Consider the following AR(1) model with\
+  \ the disturbances having zero mean and unit variance\nyt = 0.2 + 0.4 yt-1 + ut\n\
+  The (unconditional) mean of y will be given by\n(A) 0.2 (B) 0.4 (C) 0.5 (D) 0.33\n\
+  A: Let's think step by step. We refer to Wikipedia articles on econometrics for\
+  \ help. Let’s solve this problem step by step. If we have a an AR(1) model with\
+  \ the disturbances having zero mean and unit variance, then the unconditional mean\
+  \ of y is equal to the following:\nunconditional mean of y = (the intercept term)\
+  \ / (1 - autoregressive coefficient)\nWe know that the intercept term is 0.2 and\
+  \ the autoregressive coefficient is 0.4; thus, we have:\nunconditional mean of y\
+  \ = (0.2) / (1 - 0.4) = (0.2) / (0.6) = 2 / 6 = 1 / 3, which is approximately 0.33.\
+  \ That means that the answer should be (D) 0.33. The answer is (D).\n\nQ: What would\
+  \ be then consequences for the OLS estimator if heteroscedasticity is present in\
+  \ a regression model but ignored?\n(A) It will be biased (B) It will be inconsistent\
+  \ (C) It will be inefficient (D) All of (a), (b) and (c) will be true.\nA: Let's\
+  \ think step by step. We refer to Wikipedia articles on econometrics for help. Heteroscedasticity\
+  \ refers to the condition where the variance of the error terms is not constant\
+  \ across multiple observations. If heteroscedasticity is present in a regression\
+  \ model, then the coefficient estimates in the OLS estimator will be not only unbiased\
+  \ and consistent but also inefficient. Because (A) and (B) are incorrect choices\
+  \ and (C) is a correct choice, (D) cannot be the right answer. Ultimately, (C) is\
+  \ the only true choice. The answer is (C).\n\nQ: Suppose that a test statistic has\
+  \ associated with it a p-value of 0.08. Which one of the following statements is\
+  \ true?\n(i) If the size of the test were exactly 8%, we would be indifferent between\
+  \ rejecting and not rejecting the null hypothesis\n(ii) The null would be rejected\
+  \ if a 10% size of test were used\n(iii) The null would not be rejected if a 1%\
+  \ size of test were used\n(iv) The null would be rejected if a 5% size of test were\
+  \ used.\n(A) (ii) and (iv) only (B) (i) and (iii) only (C) (i), (ii), and (iii)\
+  \ only (D) (i), (ii), (iii), and (iv).\nA: Let's think step by step. We refer to\
+  \ Wikipedia articles on econometrics for help. Let’s reason about each of the options.\n\
+  (i) is a true statement.\n(ii) is a true statement.\n(iii) is a true statement.\n\
+  (iv) is not a true statement. Thus, (i), (ii), and (iii) are true. The answer is\
+  \ (C).\n\nQ: For a stationary autoregressive process, shocks will\n(A) Eventually\
+  \ die away (B) Persist indefinitely (C) Grow exponentially (D) Never occur\nA: Let's\
+  \ think step by step. We refer to Wikipedia articles on econometrics for help. This\
+  \ is a formal logic problem about stationally process. For a stationary autoregressive\
+  \ process, shocks will eventually die away. The answer is (A)."
+"group": "mmlu_flan_cot_fewshot_social_sciences"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_econometrics"

lm_eval/tasks/mmlu/flan_cot_fewshot/mmlu_electrical_engineering.yaml

-dataset_name: electrical_engineering
-description: "\nThe following are multiple choice questions (with answers) about electrical\
-  \ engineering.\n\nQ: A point pole has a strength of 4\u03C0 * 10^-4 weber. The force\
-  \ in newtons on a point pole of 4\u03C0 * 1.5 * 10^-4 weber placed at a distance\
+"dataset_name": "electrical_engineering"
+"description": "\nThe following are multiple choice questions (with answers) about\
+  \ electrical engineering.\n\nQ: A point pole has a strength of 4π * 10^-4 weber.\
+  \ The force in newtons on a point pole of 4π * 1.5 * 10^-4 weber placed at a distance\
   \ of 10 cm from it will be\n(A) 15 N. (B) 20 N. (C) 7.5 N. (D) 3.75 N.\nA: Let's\
   \ think step by step. The force between two point poles is given by m_1m_2/(mu_0\
-  \ 4 \\pi r^2), in analogy to Coulomb\u2019s law. Plugging in the values given in\
-  \ the question, we calculate that the force is approximately 15 N. The answer is\
-  \ (A).\n\nQ: The coil of a moving coil meter has 100 turns, is 40 mm long and 30\
-  \ mm wide. The control torque is 240*10-6 N-m on full scale. If magnetic flux density\
-  \ is 1Wb/m2 range of meter is\n(A) 1 mA. (B) 2 mA. (C) 3 mA. (D) 4 mA.\nA: Let's\
-  \ think step by step. The torque on a coil in a uniform magnetic field is given\
-  \ by BANI, where B is the magnetic flux density, A is the area of the coil, N is\
-  \ the number of turns, and I is the current. So we have that I = (Torque)/(BAN),\
-  \ or 240e-6/(1200e-6 * 100 * 1) = 2e-3. The answer is (B).\n\nQ: In an SR latch\
-  \ built from NOR gates, which condition is not allowed\n(A) S=0, R=0 (B) S=0, R=1\
-  \ (C) S=1, R=0 (D) S=1, R=1\nA: Let's think step by step. An SR latch is a set-reset\
-  \ latch; in the case where S=1 and R=1, the circuit has no stable state; instead\
-  \ a race condition will be produced within the circuit, so the device will be in\
-  \ an undefined state. So S=1, R=1 is an illegal input. The answer is (D).\n\nQ:\
-  \ Two long parallel conductors carry 100 A. If the conductors are separated by 20\
-  \ mm, the force per meter of length of each conductor will be\n(A) 100 N. (B) 0.1\
-  \ N. (C) 1 N. (D) 0.01 N.\nA: Let's think step by step. The magnetic force-per-length\
-  \ between two current-carrying conductors is given by \\mu_0 I_1 I_2 / (2 \\pi r),\
-  \ where $r$ is the separation distance and I_1 and I_2 are the currents. Plugging\
-  \ in 100 A for I_1 and I_2, and 20 mm for r, gives 0.1 N. The answer is (B).\n\n\
-  Q: In a 2 pole lap winding dc machine , the resistance of one conductor is 2\u03A9\
-  \ and total number of conductors is 100. Find the total resistance\n(A) 200\u03A9\
-  \ (B) 100\u03A9 (C) 50\u03A9 (D) 10\u03A9\nA: Let's think step by step. In lap winding,\
-  \ effectively two resistors are connected in parallel, so the actual resistance\
-  \ of each pair is 1 Ohm. Since we have 50 pairs, we get a total resistance of 50\
-  \ Ohms. The answer is (C)."
-include: _mmlu_flan_cot_fewshot_template_yaml
-task: mmlu_flan_cot_fewshot_electrical_engineering
+  \ 4 \\pi r^2), in analogy to Coulomb’s law. Plugging in the values given in the\
+  \ question, we calculate that the force is approximately 15 N. The answer is (A).\n\
+  \nQ: The coil of a moving coil meter has 100 turns, is 40 mm long and 30 mm wide.\
+  \ The control torque is 240*10-6 N-m on full scale. If magnetic flux density is\
+  \ 1Wb/m2 range of meter is\n(A) 1 mA. (B) 2 mA. (C) 3 mA. (D) 4 mA.\nA: Let's think\
+  \ step by step. The torque on a coil in a uniform magnetic field is given by BANI,\
+  \ where B is the magnetic flux density, A is the area of the coil, N is the number\
+  \ of turns, and I is the current. So we have that I = (Torque)/(BAN), or 240e-6/(1200e-6\
+  \ * 100 * 1) = 2e-3. The answer is (B).\n\nQ: In an SR latch built from NOR gates,\
+  \ which condition is not allowed\n(A) S=0, R=0 (B) S=0, R=1 (C) S=1, R=0 (D) S=1,\
+  \ R=1\nA: Let's think step by step. An SR latch is a set-reset latch; in the case\
+  \ where S=1 and R=1, the circuit has no stable state; instead a race condition will\
+  \ be produced within the circuit, so the device will be in an undefined state. So\
+  \ S=1, R=1 is an illegal input. The answer is (D).\n\nQ: Two long parallel conductors\
+  \ carry 100 A. If the conductors are separated by 20 mm, the force per meter of\
+  \ length of each conductor will be\n(A) 100 N. (B) 0.1 N. (C) 1 N. (D) 0.01 N.\n\
+  A: Let's think step by step. The magnetic force-per-length between two current-carrying\
+  \ conductors is given by \\mu_0 I_1 I_2 / (2 \\pi r), where $r$ is the separation\
+  \ distance and I_1 and I_2 are the currents. Plugging in 100 A for I_1 and I_2,\
+  \ and 20 mm for r, gives 0.1 N. The answer is (B).\n\nQ: In a 2 pole lap winding\
+  \ dc machine , the resistance of one conductor is 2Ω and total number of conductors\
+  \ is 100. Find the total resistance\n(A) 200Ω (B) 100Ω (C) 50Ω (D) 10Ω\nA: Let's\
+  \ think step by step. In lap winding, effectively two resistors are connected in\
+  \ parallel, so the actual resistance of each pair is 1 Ohm. Since we have 50 pairs,\
+  \ we get a total resistance of 50 Ohms. The answer is (C)."
+"group": "mmlu_flan_cot_fewshot_stem"
+"include": "_mmlu_flan_cot_fewshot_template_yaml"
+"task": "mmlu_flan_cot_fewshot_electrical_engineering"