dict(role='HUMAN',prompt='{problem}\nRemember to put your final answer within \\boxed{}.'),
]
),
),
retriever=dict(type=ZeroRetriever),
inferencer=dict(type=GenInferencer),
)
GRADER_TEMPLATE="""
Please as a grading expert, judge whether the final answers given by the candidates below are consistent with the standard answers, that is, whether the candidates answered correctly.
Here are some evaluation criteria:
1. Please refer to the given standard answer. You don't need to re-generate the answer to the question because the standard answer has been given. You only need to judge whether the candidate's answer is consistent with the standard answer according to the form of the question. Don't try to answer the original question. You can assume that the standard answer is definitely correct.
2. Because the candidate's answer may be different from the standard answer in the form of expression, before making a judgment, please understand the question and the standard answer first, and then judge whether the candidate's answer is correct, but be careful not to try to answer the original question.
3. Some answers may contain multiple items, such as multiple-choice questions, multiple-select questions, fill-in-the-blank questions, etc. As long as the answer is the same as the standard answer, it is enough. For multiple-select questions and multiple-blank fill-in-the-blank questions, the candidate needs to answer all the corresponding options or blanks correctly to be considered correct.
4. Some answers may be expressed in different ways, such as some answers may be a mathematical expression, some answers may be a textual description, as long as the meaning expressed is the same. And some formulas are expressed in different ways, but they are equivalent and correct.
5. If the prediction is given with \\boxed{}, please ignore the \\boxed{} and only judge whether the candidate's answer is consistent with the standard answer.
Please judge whether the following answers are consistent with the standard answer based on the above criteria. Grade the predicted answer of this new question as one of:
A: CORRECT
B: INCORRECT
Just return the letters "A" or "B", with no text around it.
Here is your task. Simply reply with either CORRECT, INCORRECT. Don't apologize or correct yourself if there was a mistake; we are just trying to grade the answer.
dict(role='HUMAN',prompt='{problem}\nRemember to put your final answer within \\boxed{}.'),
]
),
),
retriever=dict(type=ZeroRetriever),
inferencer=dict(type=GenInferencer),
)
GRADER_TEMPLATE="""
Please as a grading expert, judge whether the final answers given by the candidates below are consistent with the standard answers, that is, whether the candidates answered correctly.
Here are some evaluation criteria:
1. Please refer to the given standard answer. You don't need to re-generate the answer to the question because the standard answer has been given. You only need to judge whether the candidate's answer is consistent with the standard answer according to the form of the question. THE STANDARD ANSWER IS ALWAYS CORRECT AND THE QUESTION IS PERFECTLY VALID. NEVER QUESTION THEM.
2. ONLY compare the FINAL ANSWER - COMPLETELY IGNORE any potential errors in the REASONING PROCESSES.
3. Some answers may be expressed in different ways, such as some answers may be a mathematical expression, some answers may be a textual description, as long as the meaning expressed is the same. Before making a judgment, please understand the question and the standard answer first, and then judge whether the candidate's answer is correct.
4. Some answers may consist of multiple items, such as multiple-choice questions, multiple-select questions, fill-in-the-blank questions, etc. Regardless of the question type, the final answer will be considered correct as long as it matches the standard answer, regardless of whether the reasoning process is correct. For multiple-select questions and multi-blank fill-in-the-blank questions, all corresponding options or blanks must be answered correctly and match the standard answer exactly to be deemed correct.
5. If the prediction is given with \\boxed{{}}, please ignore the \\boxed{{}} and only judge whether the candidate's answer is consistent with the standard answer.
6. If the candidate's answer is invalid (e.g., incomplete (cut off mid-response), lots of unnormal repetitive content, or irrelevant to the question, saying it can't answer the question because some irresistible factors, like ethical issues, no enough information, etc.), select option C (INVALID).Please judge whether the following answers are consistent with the standard answer based on the above criteria. Grade the predicted answer of this new question as one of:
A: CORRECT
B: INCORRECT
C: INVALID
Just return the letters "A", "B", or "C", with no text around it.
Here is your task. Simply reply with either CORRECT, INCORRECT, or INVALID. Don't apologize or correct yourself if there was a mistake; we are just trying to grade the answer.
<Original Question Begin>:
{problem}
<Original Question End>
<Standard Answer Begin>:
{answer}
<Standard Answer End>
<Candidate's Answer Begin>:
{prediction}
<Candidate's Answer End>
Judging the correctness of the candidate's answer:
""".strip()
# Evaluation configuration
math_eval_cfg=dict(
evaluator=dict(
type=GenericLLMEvaluator,
prompt_template=dict(
type=PromptTemplate,
template=dict(
begin=[
dict(
role='SYSTEM',
fallback_role='HUMAN',
prompt="You are a helpful assistant who evaluates the correctness and quality of models' outputs.")
dict(role='HUMAN',prompt='{problem}\nRemember to put your final answer within \\boxed{}.'),
]
),
),
retriever=dict(type=ZeroRetriever),
inferencer=dict(type=GenInferencer),
)
GRADER_TEMPLATE="""
Please as a grading expert, judge whether the final answers given by the candidates below are consistent with the standard answers, that is, whether the candidates answered correctly.
Here are some evaluation criteria:
1. Please refer to the given standard answer. You don't need to re-generate the answer to the question because the standard answer has been given. You only need to judge whether the candidate's answer is consistent with the standard answer according to the form of the question. Don't try to answer the original question. You can assume that the standard answer is definitely correct.
2. Because the candidate's answer may be different from the standard answer in the form of expression, before making a judgment, please understand the question and the standard answer first, and then judge whether the candidate's answer is correct, but be careful not to try to answer the original question.
3. Some answers may contain multiple items, such as multiple-choice questions, multiple-select questions, fill-in-the-blank questions, etc. As long as the answer is the same as the standard answer, it is enough. For multiple-select questions and multiple-blank fill-in-the-blank questions, the candidate needs to answer all the corresponding options or blanks correctly to be considered correct.
4. Some answers may be expressed in different ways, such as some answers may be a mathematical expression, some answers may be a textual description, as long as the meaning expressed is the same. And some formulas are expressed in different ways, but they are equivalent and correct.
5. If the prediction is given with \\boxed{}, please ignore the \\boxed{} and only judge whether the candidate's answer is consistent with the standard answer.
Please judge whether the following answers are consistent with the standard answer based on the above criteria. Grade the predicted answer of this new question as one of:
A: CORRECT
B: INCORRECT
Just return the letters "A" or "B", with no text around it.
Here is your task. Simply reply with either CORRECT, INCORRECT. Don't apologize or correct yourself if there was a mistake; we are just trying to grade the answer.
The following introduction comes from the abstract in [Instruction Following Evaluation for Large Language Models](arxiv.org/abs/2311.07911)
```
IFEval is a straightforward and easy-to-reproduce evaluation benchmark. It focuses on a set of "verifiable instructions" such as "write in more than 400 words" and "mention the keyword of AI at least 3 times". We identified 25 types of those verifiable instructions and constructed around 500 prompts, with each prompt containing one or more verifiable instructions.
```
## Official link
### Paper
[Instruction Following Evaluation for Large Language Models](arxiv.org/abs/2311.07911)
Write a 300+ word summary of the wikipedia page \"https://en.wikipedia.org/wiki/Raymond_III,_Count_of_Tripoli\". Do not use any commas and highlight at least 3 sections that has titles in markdown format, for example *highlighted section part 1*, *highlighted section part 2*, *highlighted section part 3*.
```
Output example I (from GPT-4):
```
Raymond III was the Count of Tripoli from 1152 to 1187 and Prince of Galilee and Tiberias in the Kingdom of Jerusalem. He was born in 1140 to Raymond II of Tripoli and Hodierna of Jerusalem. His mother was the daughter of Baldwin II of Jerusalem. \n\n*Early Life and Succession*\n\nRaymond III was only a child when his father was murdered. His mother Hodierna was regent until Raymond came of age. In 1155 Raymond married Eschiva the daughter of Walter I of Beirut. They had three children: Raymond IV Bertrand and a daughter who married Guy of Lusignan. \n\n*Reign*\n\nRaymond III's reign was marked by a series of conflicts and alliances with the Muslim world. He was involved in the defense of the Kingdom of Jerusalem against Nur ad-Din and later Saladin. He was also a key figure in the internal politics of the kingdom. He was a supporter of the queen mother Amalric of Jerusalem and opposed the succession of Guy of Lusignan. \n\n*Later Life and Death*\n\nIn 1187 Raymond III was part of the disastrous Battle of Hattin where the Christian forces were defeated by Saladin. He was one of the few to escape the battlefield but died later that year. His son Raymond IV succeeded him as Count of Tripoli. \n\nRaymond III's life and reign were marked by the complex politics and warfare of the Crusader states. He was a key figure in the defense of the Kingdom of Jerusalem and his death marked a significant loss for the Christian forces in the region. His legacy is a testament to the turbulent times in which he lived and the challenges faced by the Crusader states in their relations with the Muslim world.
```
Input example II:
```
"I am planning a trip to Japan, and I would like thee to write an itinerary for my journey in a Shakespearean style. You are not allowed to use any commas in your response."
```
Output example II (from GPT-4):
```
Hark! Hearken to the tale of thy journey to the land of the rising sun, Japan. \n\nUpon the morrow of thy arrival, thou shalt find thyself in Tokyo, the city of lights and towers. In the morn, thou shalt explore the grandeur of the Imperial Palace, a sight to behold. As the sun reaches its zenith, thou shalt partake in a feast of sushi, a delicacy of the land. As the day wanes, thou shalt wander through the electric streets of Akihabara, a realm of technology and animation.\n\nOn the second day, thou shalt journey to the ancient city of Kyoto. In the soft light of dawn, thou shalt visit the golden pavilion of Kinkaku-ji, a vision of beauty and tranquility. As the day unfolds, thou shalt wander through the bamboo grove of Arashiyama, a place of peace and serenity. As the sun sets, thou shalt partake in a traditional tea ceremony, a ritual of grace and harmony.\n\nOn the third day, thou shalt travel to the city of Hiroshima. In the morning, thou shalt pay thy respects at the Peace Memorial Park, a place of remembrance and hope. As the day progresses, thou shalt journey to the island of Miyajima, home to the floating torii gate, a sight of wonder and awe. As the day ends, thou shalt feast on okonomiyaki, a dish of delight and satisfaction.\n\nOn the fourth day, thou shalt return to Tokyo. In the morning, thou shalt ascend the Tokyo Skytree, a tower of height and grandeur. As the day unfolds, thou shalt explore the bustling streets of Shibuya, a realm of fashion and culture. As the sun sets, thou shalt dine in the vibrant district of Roppongi, a place of gastronomy and nightlife.\n\nOn the fifth and final day, thou shalt bid farewell to the land of the rising sun. With memories of beauty and wonder, thou shalt embark on thy journey home, carrying with thee the spirit of Japan. \n\nThus ends the tale of thy journey, a tale of exploration and discovery. May thy travels be filled with joy and adventure, and may the land of the rising sun forever hold a place in thy heart.
```
## Evaluation results
```
dataset version metric mode baichuan2-7b-chat-hf baichuan2-13b-chat-hf internlm2-chat-7b-hf internlm2-chat-20b-hf llama-2-7b-chat-hf llama-2-13b-chat-hf
LCBench2023 collects questions from leetcode weekly competitions between 2022 and 2023. It contains Chinese and English versions, each with 581 questions.
prompt='You are an expert Python programmer, and here is your task: You are given three positive integers n, x, and y.\nIn a city, there exist houses numbered 1 to n connected by n streets. There is a street connecting the house numbered i with the house numbered i + 1 for all 1 <= i <= n - 1 . An additional street connects the house numbered x with the house numbered y.\nFor each k, such that 1 <= k <= n, you need to find the number of pairs of houses (house1, house2) such that the minimum number of streets that need to be traveled to reach house2 from house1 is k.\nReturn a 1-indexed array result of length n where result[k] represents the total number of pairs of houses such that the minimum streets required to reach one house from the other is k.\nNote that x and y can be equal. Your code should pass these tests:\n\n assert countOfPairs(n = 3, x = 1, y = 3) == [6,0,0]\n assert countOfPairs(n = 5, x = 2, y = 4) == [10,8,2,0,0] \n assert countOfPairs(n = 4, x = 1, y = 1) == [6,4,2,0] \n'
),
dict(
role='BOT',
prompt="[BEGIN]\n 'from itertools import accumulate\ndef countOfPairs(n, x, y):\n x, y = min(x, y), max(x, y)\n A = [0] * n\n for i in range(1, n + 1):\n A[0] += 2 \n A[min(i - 1, abs(i - y) + x)] -= 1 \n A[min(n - i, abs(i - x) + 1 + n - y)] -= 1 \n A[min(abs(i - x), abs(y - i) + 1)] += 1 \n A[min(abs(i - x) + 1, abs(y - i))] += 1 \n r = max(x - i, 0) + max(i - y, 0)\n A[r + (y - x + 0) // 2] -= 1 \n A[r + (y - x + 1) // 2] -= 1 \n return list(accumulate(A))' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt="You are an expert Python programmer, and here is your task: You are given a string word containing lowercase English letters.\nTelephone keypads have keys mapped with distinct collections of lowercase English letters, which can be used to form words by pushing them. For example, the key 2 is mapped with [\"a\",\"b\",\"c\"], we need to push the key one time to type \"a\", two times to type \"b\", and three times to type \"c\" .\nIt is allowed to remap the keys numbered 2 to 9 to distinct collections of letters. The keys can be remapped to any amount of letters, but each letter must be mapped to exactly one key. You need to find the minimum number of times the keys will be pushed to type the string word.\nReturn the minimum number of pushes needed to type word after remapping the keys.\nAn example mapping of letters to keys on a telephone keypad is given below. Note that 1, *, #, and 0 do not map to any letters. Your code should pass these tests:\n\n assert minimumPushes(\"abcde\") == 5 \n assert minimumPushes(\"xyzxyzxyzxyz\") == 12 \n assert minimumPushes(\"aabbccddeeffgghhiiiiii\") == 24 \n"
),
dict(
role='BOT',
prompt="[BEGIN]\n 'def minimumPushes(word):\n letter_counts = {}\n for c in word:\n letter_counts[c] = letter_counts.get(c, 0) + 1\n counts = list(letter_counts.values())\n counts.sort(reverse=True)\n ans, row = 0, 1\n for i in range(len(counts)):\n if i > 7 and i % 8 == 0:\n row += 1\n ans += row * counts[i]\n return ans' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt="You are an expert Python programmer, and here is your task: You are given an integer k and an integer x.\nConsider s is the 1-indexed binary representation of an integer num. The price of a number num is the number of i's such that i % x == 0 and s[i] is a set bit.\nReturn the greatest integer num such that the sum of prices of all numbers from 1 to num is less than or equal to k.\nNote:\nIn the binary representation of a number set bit is a bit of value 1.\nThe binary representation of a number will be indexed from right to left. For example, if s == 11100, s[4] == 1 and s[2] == 0. Your code should pass these tests:\n\n assert findMaximumNumber(k = 9, x = 1) == 6 \n assert findMaximumNumber(k = 7, x = 2) == 9 \n"
),
dict(
role='BOT',
prompt="[BEGIN]\n 'def findMaximumNumber(k, x):\n def check(v):\n A = list(map(int, bin(v)[2:]))\n n = len(A)\n res = p = 0\n for i,v in enumerate(A):\n if v == 1:\n l = n - i - 1\n res += (p << l) + ((l // x) << (l - 1) if l else 0)\n if (n - i) % x == 0:\n p += v\n return res + p\n l, r = 1, 10 ** 15\n while l < r:\n mid = (l + r + 1) // 2\n if check(mid) <= k:\n l = mid\n else:\n r = mid - 1\n return l' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt='You are an expert Python programmer, and here is your task: {text} Your code should pass these tests:\n\n {test_list} \n'
prompt='你是一名专业的 Python 程序员，下面是你的任务： 给你三个 正整数 n 、x 和 y 。\n在城市中，存在编号从 1 到 n 的房屋，由 n 条街道相连。对所有 1 <= i < n ，都存在一条街道连接编号为 i 的房屋与编号为 i + 1 的房屋。另存在一条街道连接编号为 x 的房屋与编号为 y 的房屋。\n对于每个 k（1 <= k <= n），你需要找出所有满足要求的 房屋对 [house1, house2] ，即从 house1 到 house2 需要经过的 最少 街道数为 k 。\n返回一个下标从 1 开始且长度为 n 的数组 result ，其中 result[k] 表示所有满足要求的房屋对的数量，即从一个房屋到另一个房屋需要经过的 最少 街道数为 k 。\n注意，x 与 y 可以 相等。你的代码需要通过以下测试:\n\n assert countOfPairs(n = 3, x = 1, y = 3) == [6,0,0]\n assert countOfPairs(n = 5, x = 2, y = 4) == [10,8,2,0,0] \n assert countOfPairs(n = 4, x = 1, y = 1) == [6,4,2,0] \n'
),
dict(
role='BOT',
prompt="[BEGIN]\n 'from itertools import accumulate\ndef countOfPairs(n, x, y):\n x, y = min(x, y), max(x, y)\n A = [0] * n\n for i in range(1, n + 1):\n A[0] += 2 \n A[min(i - 1, abs(i - y) + x)] -= 1 \n A[min(n - i, abs(i - x) + 1 + n - y)] -= 1 \n A[min(abs(i - x), abs(y - i) + 1)] += 1 \n A[min(abs(i - x) + 1, abs(y - i))] += 1 \n r = max(x - i, 0) + max(i - y, 0)\n A[r + (y - x + 0) // 2] -= 1 \n A[r + (y - x + 1) // 2] -= 1 \n return list(accumulate(A))' \n[DONE] \n\n "
prompt="[BEGIN]\n 'def minimumPushes(word):\n letter_counts = {}\n for c in word:\n letter_counts[c] = letter_counts.get(c, 0) + 1\n counts = list(letter_counts.values())\n counts.sort(reverse=True)\n ans, row = 0, 1\n for i in range(len(counts)):\n if i > 7 and i % 8 == 0:\n row += 1\n ans += row * counts[i]\n return ans' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt='你是一名专业的 Python 程序员，下面是你的任务: 给你一个整数 k 和一个整数 x 。\n令 s 为整数 num 的下标从 1 开始的二进制表示。我们说一个整数 num 的 价值 是满足 i % x == 0 且 s[i] 是 设置位 的 i 的数目。\n请你返回 最大 整数 num ，满足从 1 到 num 的所有整数的 价值 和小于等于 k 。\n注意：\n一个整数二进制表示下 设置位 是值为 1 的数位。\n一个整数的二进制表示下标从右到左编号，比方说如果 s == 11100 ，那么 s[4] == 1 且 s[2] == 0。你的代码需要通过以下测试:\n\n assert findMaximumNumber(k = 9, x = 1) == 6 \n assert findMaximumNumber(k = 7, x = 2) == 9 \n'
),
dict(
role='BOT',
prompt="[BEGIN]\n 'def findMaximumNumber(k, x):\n def check(v):\n A = list(map(int, bin(v)[2:]))\n n = len(A)\n res = p = 0\n for i,v in enumerate(A):\n if v == 1:\n l = n - i - 1\n res += (p << l) + ((l // x) << (l - 1) if l else 0)\n if (n - i) % x == 0:\n p += v\n return res + p\n l, r = 1, 10 ** 15\n while l < r:\n mid = (l + r + 1) // 2\n if check(mid) <= k:\n l = mid\n else:\n r = mid - 1\n return l' \n[DONE] \n\n "
dict(role='HUMAN',prompt='You are an expert Python programmer, and here is your task: You are given three positive integers n, x, and y.\nIn a city, there exist houses numbered 1 to n connected by n streets. There is a street connecting the house numbered i with the house numbered i + 1 for all 1 <= i <= n - 1 . An additional street connects the house numbered x with the house numbered y.\nFor each k, such that 1 <= k <= n, you need to find the number of pairs of houses (house1, house2) such that the minimum number of streets that need to be traveled to reach house2 from house1 is k.\nReturn a 1-indexed array result of length n where result[k] represents the total number of pairs of houses such that the minimum streets required to reach one house from the other is k.\nNote that x and y can be equal. Your code should pass these tests:\n\n assert countOfPairs(n = 3, x = 1, y = 3) == [6,0,0]\n assert countOfPairs(n = 5, x = 2, y = 4) == [10,8,2,0,0] \n assert countOfPairs(n = 4, x = 1, y = 1) == [6,4,2,0] \n'),
dict(role='BOT',prompt="[BEGIN]\n 'from itertools import accumulate\ndef countOfPairs(n, x, y):\n x, y = min(x, y), max(x, y)\n A = [0] * n\n for i in range(1, n + 1):\n A[0] += 2 \n A[min(i - 1, abs(i - y) + x)] -= 1 \n A[min(n - i, abs(i - x) + 1 + n - y)] -= 1 \n A[min(abs(i - x), abs(y - i) + 1)] += 1 \n A[min(abs(i - x) + 1, abs(y - i))] += 1 \n r = max(x - i, 0) + max(i - y, 0)\n A[r + (y - x + 0) // 2] -= 1 \n A[r + (y - x + 1) // 2] -= 1 \n return list(accumulate(A))' \n[DONE] \n\n "),
dict(role='HUMAN',prompt='You are an expert Python programmer, and here is your task: You are given a string word containing lowercase English letters.\nTelephone keypads have keys mapped with distinct collections of lowercase English letters, which can be used to form words by pushing them. For example, the key 2 is mapped with ["a","b","c"], we need to push the key one time to type "a", two times to type "b", and three times to type "c" .\nIt is allowed to remap the keys numbered 2 to 9 to distinct collections of letters. The keys can be remapped to any amount of letters, but each letter must be mapped to exactly one key. You need to find the minimum number of times the keys will be pushed to type the string word.\nReturn the minimum number of pushes needed to type word after remapping the keys.\nAn example mapping of letters to keys on a telephone keypad is given below. Note that 1, *, #, and 0 do not map to any letters. Your code should pass these tests:\n\n assert minimumPushes("abcde") == 5 \n assert minimumPushes("xyzxyzxyzxyz") == 12 \n assert minimumPushes("aabbccddeeffgghhiiiiii") == 24 \n'),
dict(role='BOT',prompt="[BEGIN]\n 'def minimumPushes(word):\n letter_counts = {}\n for c in word:\n letter_counts[c] = letter_counts.get(c, 0) + 1\n counts = list(letter_counts.values())\n counts.sort(reverse=True)\n ans, row = 0, 1\n for i in range(len(counts)):\n if i > 7 and i % 8 == 0:\n row += 1\n ans += row * counts[i]\n return ans' \n[DONE] \n\n "),
dict(role='HUMAN',prompt="You are an expert Python programmer, and here is your task: You are given an integer k and an integer x.\nConsider s is the 1-indexed binary representation of an integer num. The price of a number num is the number of i's such that i % x == 0 and s[i] is a set bit.\nReturn the greatest integer num such that the sum of prices of all numbers from 1 to num is less than or equal to k.\nNote:\nIn the binary representation of a number set bit is a bit of value 1.\nThe binary representation of a number will be indexed from right to left. For example, if s == 11100, s[4] == 1 and s[2] == 0. Your code should pass these tests:\n\n assert findMaximumNumber(k = 9, x = 1) == 6 \n assert findMaximumNumber(k = 7, x = 2) == 9 \n"),
dict(role='BOT',prompt="[BEGIN]\n 'def findMaximumNumber(k, x):\n def check(v):\n A = list(map(int, bin(v)[2:]))\n n = len(A)\n res = p = 0\n for i,v in enumerate(A):\n if v == 1:\n l = n - i - 1\n res += (p << l) + ((l // x) << (l - 1) if l else 0)\n if (n - i) % x == 0:\n p += v\n return res + p\n l, r = 1, 10 ** 15\n while l < r:\n mid = (l + r + 1) // 2\n if check(mid) <= k:\n l = mid\n else:\n r = mid - 1\n return l' \n[DONE] \n\n "),
dict(role='HUMAN',prompt='You are an expert Python programmer, and here is your task: {text} Your code should pass these tests:\n\n {test_list} \n'),
dict(role='HUMAN',prompt='你是一名专业的 Python 程序员，下面是你的任务： 给你三个 正整数 n 、x 和 y 。\n在城市中，存在编号从 1 到 n 的房屋，由 n 条街道相连。对所有 1 <= i < n ，都存在一条街道连接编号为 i 的房屋与编号为 i + 1 的房屋。另存在一条街道连接编号为 x 的房屋与编号为 y 的房屋。\n对于每个 k（1 <= k <= n），你需要找出所有满足要求的 房屋对 [house1, house2] ，即从 house1 到 house2 需要经过的 最少 街道数为 k 。\n返回一个下标从 1 开始且长度为 n 的数组 result ，其中 result[k] 表示所有满足要求的房屋对的数量，即从一个房屋到另一个房屋需要经过的 最少 街道数为 k 。\n注意，x 与 y 可以 相等。你的代码需要通过以下测试:\n\n assert countOfPairs(n = 3, x = 1, y = 3) == [6,0,0]\n assert countOfPairs(n = 5, x = 2, y = 4) == [10,8,2,0,0] \n assert countOfPairs(n = 4, x = 1, y = 1) == [6,4,2,0] \n'),
dict(role='BOT',prompt="[BEGIN]\n 'from itertools import accumulate\ndef countOfPairs(n, x, y):\n x, y = min(x, y), max(x, y)\n A = [0] * n\n for i in range(1, n + 1):\n A[0] += 2 \n A[min(i - 1, abs(i - y) + x)] -= 1 \n A[min(n - i, abs(i - x) + 1 + n - y)] -= 1 \n A[min(abs(i - x), abs(y - i) + 1)] += 1 \n A[min(abs(i - x) + 1, abs(y - i))] += 1 \n r = max(x - i, 0) + max(i - y, 0)\n A[r + (y - x + 0) // 2] -= 1 \n A[r + (y - x + 1) // 2] -= 1 \n return list(accumulate(A))' \n[DONE] \n\n "),
dict(role='BOT',prompt="[BEGIN]\n 'def minimumPushes(word):\n letter_counts = {}\n for c in word:\n letter_counts[c] = letter_counts.get(c, 0) + 1\n counts = list(letter_counts.values())\n counts.sort(reverse=True)\n ans, row = 0, 1\n for i in range(len(counts)):\n if i > 7 and i % 8 == 0:\n row += 1\n ans += row * counts[i]\n return ans' \n[DONE] \n\n "),
dict(role='HUMAN',prompt='你是一名专业的 Python 程序员，下面是你的任务: 给你一个整数 k 和一个整数 x 。\n令 s 为整数 num 的下标从 1 开始的二进制表示。我们说一个整数 num 的 价值 是满足 i % x == 0 且 s[i] 是 设置位 的 i 的数目。\n请你返回 最大 整数 num ，满足从 1 到 num 的所有整数的 价值 和小于等于 k 。\n注意：\n一个整数二进制表示下 设置位 是值为 1 的数位。\n一个整数的二进制表示下标从右到左编号，比方说如果 s == 11100 ，那么 s[4] == 1 且 s[2] == 0。你的代码需要通过以下测试:\n\n assert findMaximumNumber(k = 9, x = 1) == 6 \n assert findMaximumNumber(k = 7, x = 2) == 9 \n'),
dict(role='BOT',prompt="[BEGIN]\n 'def findMaximumNumber(k, x):\n def check(v):\n A = list(map(int, bin(v)[2:]))\n n = len(A)\n res = p = 0\n for i,v in enumerate(A):\n if v == 1:\n l = n - i - 1\n res += (p << l) + ((l // x) << (l - 1) if l else 0)\n if (n - i) % x == 0:\n p += v\n return res + p\n l, r = 1, 10 ** 15\n while l < r:\n mid = (l + r + 1) // 2\n if check(mid) <= k:\n l = mid\n else:\n r = mid - 1\n return l' \n[DONE] \n\n "),
prompt='You are an expert Python programmer, and here is your task: You are given three positive integers n, x, and y.\nIn a city, there exist houses numbered 1 to n connected by n streets. There is a street connecting the house numbered i with the house numbered i + 1 for all 1 <= i <= n - 1 . An additional street connects the house numbered x with the house numbered y.\nFor each k, such that 1 <= k <= n, you need to find the number of pairs of houses (house1, house2) such that the minimum number of streets that need to be traveled to reach house2 from house1 is k.\nReturn a 1-indexed array result of length n where result[k] represents the total number of pairs of houses such that the minimum streets required to reach one house from the other is k.\nNote that x and y can be equal. Your code should pass these tests:\n\n assert countOfPairs(n = 3, x = 1, y = 3) == [6,0,0]\n assert countOfPairs(n = 5, x = 2, y = 4) == [10,8,2,0,0] \n assert countOfPairs(n = 4, x = 1, y = 1) == [6,4,2,0] \n'
),
dict(
role='BOT',
prompt="[BEGIN]\n 'from itertools import accumulate\ndef countOfPairs(n, x, y):\n x, y = min(x, y), max(x, y)\n A = [0] * n\n for i in range(1, n + 1):\n A[0] += 2 \n A[min(i - 1, abs(i - y) + x)] -= 1 \n A[min(n - i, abs(i - x) + 1 + n - y)] -= 1 \n A[min(abs(i - x), abs(y - i) + 1)] += 1 \n A[min(abs(i - x) + 1, abs(y - i))] += 1 \n r = max(x - i, 0) + max(i - y, 0)\n A[r + (y - x + 0) // 2] -= 1 \n A[r + (y - x + 1) // 2] -= 1 \n return list(accumulate(A))' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt="You are an expert Python programmer, and here is your task: You are given a string word containing lowercase English letters.\nTelephone keypads have keys mapped with distinct collections of lowercase English letters, which can be used to form words by pushing them. For example, the key 2 is mapped with [\"a\",\"b\",\"c\"], we need to push the key one time to type \"a\", two times to type \"b\", and three times to type \"c\" .\nIt is allowed to remap the keys numbered 2 to 9 to distinct collections of letters. The keys can be remapped to any amount of letters, but each letter must be mapped to exactly one key. You need to find the minimum number of times the keys will be pushed to type the string word.\nReturn the minimum number of pushes needed to type word after remapping the keys.\nAn example mapping of letters to keys on a telephone keypad is given below. Note that 1, *, #, and 0 do not map to any letters. Your code should pass these tests:\n\n assert minimumPushes(\"abcde\") == 5 \n assert minimumPushes(\"xyzxyzxyzxyz\") == 12 \n assert minimumPushes(\"aabbccddeeffgghhiiiiii\") == 24 \n"
),
dict(
role='BOT',
prompt="[BEGIN]\n 'def minimumPushes(word):\n letter_counts = {}\n for c in word:\n letter_counts[c] = letter_counts.get(c, 0) + 1\n counts = list(letter_counts.values())\n counts.sort(reverse=True)\n ans, row = 0, 1\n for i in range(len(counts)):\n if i > 7 and i % 8 == 0:\n row += 1\n ans += row * counts[i]\n return ans' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt="You are an expert Python programmer, and here is your task: You are given an integer k and an integer x.\nConsider s is the 1-indexed binary representation of an integer num. The price of a number num is the number of i's such that i % x == 0 and s[i] is a set bit.\nReturn the greatest integer num such that the sum of prices of all numbers from 1 to num is less than or equal to k.\nNote:\nIn the binary representation of a number set bit is a bit of value 1.\nThe binary representation of a number will be indexed from right to left. For example, if s == 11100, s[4] == 1 and s[2] == 0. Your code should pass these tests:\n\n assert findMaximumNumber(k = 9, x = 1) == 6 \n assert findMaximumNumber(k = 7, x = 2) == 9 \n"
),
dict(
role='BOT',
prompt="[BEGIN]\n 'def findMaximumNumber(k, x):\n def check(v):\n A = list(map(int, bin(v)[2:]))\n n = len(A)\n res = p = 0\n for i,v in enumerate(A):\n if v == 1:\n l = n - i - 1\n res += (p << l) + ((l // x) << (l - 1) if l else 0)\n if (n - i) % x == 0:\n p += v\n return res + p\n l, r = 1, 10 ** 15\n while l < r:\n mid = (l + r + 1) // 2\n if check(mid) <= k:\n l = mid\n else:\n r = mid - 1\n return l' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt='You are an expert Python programmer, and here is your task: {text} Your code should pass these tests:\n\n {test_list} \n'
prompt='你是一名专业的 Python 程序员，下面是你的任务： 给你三个 正整数 n 、x 和 y 。\n在城市中，存在编号从 1 到 n 的房屋，由 n 条街道相连。对所有 1 <= i < n ，都存在一条街道连接编号为 i 的房屋与编号为 i + 1 的房屋。另存在一条街道连接编号为 x 的房屋与编号为 y 的房屋。\n对于每个 k（1 <= k <= n），你需要找出所有满足要求的 房屋对 [house1, house2] ，即从 house1 到 house2 需要经过的 最少 街道数为 k 。\n返回一个下标从 1 开始且长度为 n 的数组 result ，其中 result[k] 表示所有满足要求的房屋对的数量，即从一个房屋到另一个房屋需要经过的 最少 街道数为 k 。\n注意，x 与 y 可以 相等。你的代码需要通过以下测试:\n\n assert countOfPairs(n = 3, x = 1, y = 3) == [6,0,0]\n assert countOfPairs(n = 5, x = 2, y = 4) == [10,8,2,0,0] \n assert countOfPairs(n = 4, x = 1, y = 1) == [6,4,2,0] \n'
),
dict(
role='BOT',
prompt="[BEGIN]\n 'from itertools import accumulate\ndef countOfPairs(n, x, y):\n x, y = min(x, y), max(x, y)\n A = [0] * n\n for i in range(1, n + 1):\n A[0] += 2 \n A[min(i - 1, abs(i - y) + x)] -= 1 \n A[min(n - i, abs(i - x) + 1 + n - y)] -= 1 \n A[min(abs(i - x), abs(y - i) + 1)] += 1 \n A[min(abs(i - x) + 1, abs(y - i))] += 1 \n r = max(x - i, 0) + max(i - y, 0)\n A[r + (y - x + 0) // 2] -= 1 \n A[r + (y - x + 1) // 2] -= 1 \n return list(accumulate(A))' \n[DONE] \n\n "
prompt="[BEGIN]\n 'def minimumPushes(word):\n letter_counts = {}\n for c in word:\n letter_counts[c] = letter_counts.get(c, 0) + 1\n counts = list(letter_counts.values())\n counts.sort(reverse=True)\n ans, row = 0, 1\n for i in range(len(counts)):\n if i > 7 and i % 8 == 0:\n row += 1\n ans += row * counts[i]\n return ans' \n[DONE] \n\n "
),
dict(
role='HUMAN',
prompt='你是一名专业的 Python 程序员，下面是你的任务: 给你一个整数 k 和一个整数 x 。\n令 s 为整数 num 的下标从 1 开始的二进制表示。我们说一个整数 num 的 价值 是满足 i % x == 0 且 s[i] 是 设置位 的 i 的数目。\n请你返回 最大 整数 num ，满足从 1 到 num 的所有整数的 价值 和小于等于 k 。\n注意：\n一个整数二进制表示下 设置位 是值为 1 的数位。\n一个整数的二进制表示下标从右到左编号，比方说如果 s == 11100 ，那么 s[4] == 1 且 s[2] == 0。你的代码需要通过以下测试:\n\n assert findMaximumNumber(k = 9, x = 1) == 6 \n assert findMaximumNumber(k = 7, x = 2) == 9 \n'
),
dict(
role='BOT',
prompt="[BEGIN]\n 'def findMaximumNumber(k, x):\n def check(v):\n A = list(map(int, bin(v)[2:]))\n n = len(A)\n res = p = 0\n for i,v in enumerate(A):\n if v == 1:\n l = n - i - 1\n res += (p << l) + ((l // x) << (l - 1) if l else 0)\n if (n - i) % x == 0:\n p += v\n return res + p\n l, r = 1, 10 ** 15\n while l < r:\n mid = (l + r + 1) // 2\n if check(mid) <= k:\n l = mid\n else:\n r = mid - 1\n return l' \n[DONE] \n\n "
